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Tcecarenko [31]
3 years ago
12

1/3x 6,000 helppp barely learning these

Mathematics
2 answers:
Tatiana [17]3 years ago
4 0

Answer:

2000

Step-by-step explanation:

my answer has to be 20 characters long.

Ipatiy [6.2K]3 years ago
3 0

Answer:

2000

Step-by-step explanation:

6000 / 3 = 2000

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Marc is looking at the plans for his new garage. the length of the garage is 8 metres. the scale on the drawing is 1:50. what wi
evablogger [386]
The answer is 16 cm (or 0.16 m).

The scale is the ratio of the model to the real thing.
So, in the scale 1:50, the model is 1, while the real thing is 50.
Now, just make a proportion:
the model : the real thing = the model dimension : the real thing dimension
        1         :          50         =                   x                 :                    8m

From here:
x = 8m * 1 / 50 = 0.16 m = 0.16 * 100 cm = 16 cm.
4 0
3 years ago
Find the value of X <br> WILL MARK BRAINLIEST IF CORRECT!
goldfiish [28.3K]

Answer:

x = 52

Step-by-step explanation:

This is a picture of a right angle, which is 90 degrees. We should first make an equation to represent this problem.

(x - 12) + 50 = 90

1. Subtract 50 from both sides of the equation.

(x - 12) = 40

2. Add 12 from both sides of the equation

x = 52

The value of x is 52.

3 0
3 years ago
Read 2 more answers
What is 9 tens more than 99 190​
Oksana_A [137]
99 plus 9 tens?? if so, 189
5 0
3 years ago
Write a number with two decimals places that is bigger than 4 1/5 but smaller then 4.25 (Could u explain so i can actually under
zubka84 [21]
<u>The possible answers are:
</u>
<u /><u /><u><em /></u>4.21
4.22
4.23
4.24

Explanation:
We want a number between 4 1/5 and 4.25.  We will convert 4 1/5 to a decimal first:

Divide 1 by 5:  1/5 = 0.2.

This makes 4 1/5 = 4 + 1/5 = 4 + 0.2 = 4.2.

We want a number between 4.2, which can be written as 4.20, and 4.25.  Any number between will do, so the possible answers would be 
4.21, 4.22, 4.23, or 4.24.<u />
7 0
3 years ago
Read 2 more answers
Use the Quadratic Formula to solve x2 + 20x + 98 = 0
Lubov Fominskaja [6]
ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\if\ \Delta \ \textless \  0\ then\ no\ solution\\\\if\ \Delta =0\ then\ one\ solution\ x_0=\dfrac{-b}{2a}\\\\if\ \Delta \ \textgreater \  0\ then\ two\ solutions\ x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\-----------------------------

x^2+20x+98=0\\a=1;\ b=20;\ c=98\\\\\Delta=20^2-4\cdot1\cdot98=400-392=8 \ \textgreater \  0\\\sqrt\Delta=\sqrt8=\sqrt{4\cdot2}=\sqrt4\cdot\sqrt2=2\sqrt2\\\\x_1=\dfrac{-20-2\sqrt2}{2\cdot1}=\dfrac{-20-2\sqrt2}{2}=-10-\sqrt2\\\\x_2=\dfrac{-20+2\sqrt2}{2\cdot1}=\dfrac{-20+2\sqrt2}{2}=-10+\sqrt2
3 0
3 years ago
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