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Savatey [412]
3 years ago
12

Answer this its attached

Mathematics
1 answer:
iogann1982 [59]3 years ago
8 0
The answer is B
Take the 7-3 to get the 4 and take the 10-1 to get the 9.
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I am really confused about this one. Even though it is really easy.
n200080 [17]

Answer:

It's d

Step-by-step explanation:

Hope it helps!!

3 0
3 years ago
Read 2 more answers
95 POINTS! PLEASE HELP!
aliina [53]

Answer:

1. 3

2. 2

3. 2

4. 6

5. No solution

Step-by-step explanation:

2x+3y=8 (1)

-6x+4y=11 (2)

3(1) + (2)

6x + 9y = 24

-6x + 4y = 11

13y = 35

y = 35/13

x = -1/26

3x-y=3 (1)

-2x+2y=6 (2)

2(1) + (2)

6x - 2y = 6

-2x + 2y = 6

4x = 12

x = 3

y = 3(3) - 3 = 6

3x+4y=-10 (1)

5x-2y=18 (2)

(1) + 2(2)

3x + 4y = -10

10x - 4y = 36

13x = 26

x = 2

5x-2y=3 (1)

2x-y=0 (2)

(1) - 2(2)

5x - 2y = 3

-4x + 2y = 0

x = 3

2(3) - y = 0

y = 6

3x+2y=10 (1)

6x+4y=14 (2)

2(1) - (2)

6x + 4y = 20

6x + 4y = 14

0 = 6 is a false statement so no solution

3 0
3 years ago
Read 2 more answers
How much interest would Mia pay if the simple interest rate were 5%
balu736 [363]

Answer:

Mia would have a 55$ interest  :)

Step-by-step explanation:

7 0
3 years ago
In each situation, write a recurrence relation, including base case(s), for the given function. briefly explain in words why thi
vova2212 [387]
A thumb-wrestling match requires two thumbs, so we can either suppose that we need at least two people (n\ge2), or allow one to thumb-wrestle one's self. In either case, we'd have t(1)=t(2)=1, so let's just say we need a minimum of two players.

If we add one more person to the set of players, then the first two people would need to play 1 additional match each. So t(3)=t(2)+2.

If we add one more person, then the first three people would again each have to play 1 more match with the new person. So t(4)=t(3)+3.

And so on, so that in general, the number of games needed for everyone to play exactly one match with everyone else is given recursively by

\begin{cases}t(2)=1\\t(n+1)=t(n)+n&\text{for }n\ge2\end{cases}
6 0
3 years ago
Simplify The following equations
Kryger [21]
Mostly collect like terms
use associative property which is
(a+b)+c=a+(b+c)
and remember that:
you just use a general rule
x+x=2x
x^2+x^2=2x^2
3xy4xy=7xy
3x+4x^2=3x+4x^2
you can only add like terms( like terms are terms that are same name like x or y are differnt, and like terms have same power exg x^2 and x^3 and x^1/2 and such


so first one



3b+11c-4c-c
since they are all c except for the first one term, just assign a number for each so it simplifies to c times(11-1)+b(3-4)=c(10-1b=10c-b or

you just use a general rule
x+x=2x
x^2+x^2=2x^2
3xy4xy=7xy
3x+4x^2=3x+4x^2




second one9a-1+8c-8a+c
group like terms
(9a-8a)+(8c+c)-1=(a)+(9c)-1=a+9c-1

12c+5a+7-13c+4a
group like terms(12c-13c)+(5a+4a)+7
add like terms
-c+9a+7
the solution is 9a-c+7


-15-6c+3b-6c+9-2b
group like terms
(-15+9)+(-6c-6c)+(3b-2b)
-6+(-12c)+b=b-6-12c



the answers are:

10c-b

a+9c-1

9a-c+7

b-12c-6

5 0
4 years ago
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