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Artyom0805 [142]
2 years ago
9

I need help to find the x

Mathematics
1 answer:
Arada [10]2 years ago
6 0

Answer:

34? (I don't know what the upper right corner says)

Step-by-step explanation:

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Dennis_Churaev [7]

Answer:

The angle of the figure is 90°

4 0
2 years ago
How do i solve these questions? <br><br> can someone please tell me thanks :)
Vika [28.1K]
To find the area of this just add the units I believe which is 21
Hope this helps good luck. Not sure if this is 100% right my last year teacher was a sucky one
6 0
3 years ago
Solve for z. 20 − (z + 7) = 0.9
zhannawk [14.2K]

Answer:

x = 12.1

Step-by-step explanation:

20 − (z + 7) = 0.9

Distribute the minus sign

20 -x -7 = .9

Combine like terms

13 -x = .9

Subtract 13 from each side

-x = -12.1

x = 12.1

7 0
3 years ago
Read 2 more answers
72-(63-8) and (72-63)-8
tatyana61 [14]
The Priority is always to parenthesis. It means that in both equations, begin by operating what's inside the parenthesis. Then Subtract what's left.

For the first one you get:
72 - (63-8)
72 - 55
17

For the second one you get:
(72-63)-8
9-8
1

Which mean that The 2 equations are not equal, because 17 \ \textgreater \  1
Hope this Helps! :D
3 0
3 years ago
Read 2 more answers
Please use picture for the question not the writing
Alex787 [66]

\tt \: f(x) =  {x}^{2}  + 4x - 1

To complete the square, the same value needs to be added to both sides

\tt \: f(x)  +  ? =  {x}^{2}  + 4x  + ? - 1

To complete the square, Add 4 on both sides of the equation

\tt \: f(x) + 4 =  {x}^{2}  + 4x + 4 - 1

Use a²+2ab+b²=(a+b)² to factor the expression

\tt \: f(x) + 4 = (x + 2)^{2}  - 1

Move the constant to the right-hand side and change its sign

\tt \: f(x) =  {(x + 2)}^{2} - 1 - 4

Calculate the difference

\tt \: f(x) =  {(x + 2)}^{2} -5

And, We are done solving!!~

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

<em>The option that corresponds our final answer is option D...</em>

7 0
3 years ago
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