Answer:
A is wrong
B is right
C is right
D is wrong ( i think )
E is wrong
2nd answer:
i disagree with timothy but cant put my reasoning into words, sorry
Answer:
C. In y^2-y=6, 6 should have been subtracted on both sides first.
Step-by-step explanation:
It is a quadratic equation so you subtract the 6 and create
y^2-y-6=0
Then you factor it to:
(y-3)(y+2)=0
The solutions then are:
y-3=0, y=3 and y+2=0, y=-2
{-2,3}
Answer:
<h3>Right π over 2 Up 2.</h3>
Step-by-step explanation:
We are given a trigonometric function f(x) = −3 cos(2x − π) + 2.
We need to explain the transformations in the given function being applied.
We can see that 2 is being added to −3 cos(2x − π) in th given function.
<em>According to rules of transformations, y=f(x)+D, shifts D units up if D is a positive number.</em>
Therefore, for adding 2 in −3 cos(2x − π), it would shift 2 units up.
Let us see other transformation being applied there.
We can see that π is being subtracted in parenthesis from 2x.
<em>According to rules of transformations, y=f(x-C), shifts C units right if C is a positive value.</em>
Therefore, on subtracting π from 2x in −3 cos(2x) inside parenthesis, the function shifts π units right.
Therefore, correct option for transformations would be :
<h3>Right π over 2 Up 2.</h3>
Answer:
f(x) = (x -2)(x -1+3i)(x -1-3i)
Step-by-step explanation:
You can use synthetic division to find the remaining quadratic factor in the cubic. Then any of the usual means of solving the quadratic will help you find its linear factors.
In the attached, I show the synthetic division, the factoring to real numbers, and the solution that finds the complex linear factors by completing the square.
Of course, you know that for zeros a, b, and c, the linear factors are ...
f(x) = (x -a)(x -b)(x -c)
Here, we have a=2, b=1-3i, c=1+3i.
f(x) = (x -2)(x -1+3i)(x -1-3i)