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3 years ago

What is the answer of 10 ( 5 + n )

Mathematics

2 answers:

Burka [1]3 years ago

5 0

1. Apply the distributive property.

10 * 5 + 10n

2. Multiply 10 by 5.

50 + 10n

3. Then divide by 10 on both sides.

50/ 10 = 5

10/ 10 = n

4. So, your answer is...

n = 5

inn [45]3 years ago

4 0

Answer:

50+n

Step-by-step explanation:

distributive property: 10 times 5 equals 50.

you are left with 50 plus n.

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−2x=x^2 minus 6, <br> Rewrite the equation by completing the square. please answer

Paul [167]

Answer:

$(x+1)^{2} -5$

Step-by-step explanation:

$-2x=x^{2} -6 \\x^{2} +2x-6\\(\frac{b}{2}) ^{2} =(\frac{2}{2}) ^{2} =1^{2} =1\\so, (x^{2} +2x+1)-6+1\\ x^{2} +2x+1=(x+1)^{2} \\-6+1=5\\(x+1)^{2} -5$

Sorry it took so long

4 0

3 years ago

Need help with this answer !!!

KengaRu [80]

To find the area of a rectangle, multiple the width by the length.

(And simply the fractions for a simpler equation)

For piece A:
The length 1 and 3/5 can be turned into an improper fraction by multiplying 1 by the denominator (5) and adding it to the numerator (3). 1 and 3/5 = 8/5

(3/4) • (8/5) = area

Multiple the numerators with each other and the denominators with each other (3 times 8 = 24) (4 times 5 = 20)

The area of piece A is 24/20

If you do the same for piece B:

(2/5) • (21/8) = area

The answer is 42/40

8 0

3 years ago

Read 2 more answers

The water diet requires you to drink two cups of water every half hour from the time you get up until you go to bed, but otherwi

Elan Coil [88]

Answer:

$7-3.182 \frac{13.638}{\sqrt{4}}= -14.698$

$7+3.182 \frac{13.638}{\sqrt{4}}= 28.698$

Step-by-step explanation:

For this case we have the following info given:

Weight before diet 180 125 240 150

Weight after diet 170 130 215 152

We define the random variable $D = before-after$ and we can calculate the inidividual values:

D: 10, -5, 25, -2

And we can calculate the mean with this formula:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

And the deviation with:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}$

And after replace we got:

$\bar D= 7, s_d = 13.638$

And the confidence interval for this case would be given by:

$\bar D \pm t_{\alpha/2} \frac{s_d}{\sqrt{n}}$

The degrees of freedom are given by:

$df = n-1= 4-1=3$

For the 95% of confidence the value for the significance is $\alpha=0.05$ and the critical value would be $t_{\alpha/2}= 3.182$ . And replacing we got: