Last angle is 122 if its a triangle
Answer:
equation of the line having slope 1/4
that passes through (8,3) is given by
y - 3 = 1/4 ( x - 8)
or, 4y - 12 = x -8
or, 4y -12 - x + 8 = 0
or, 4y - x - 4 = 0 , which is the required equation.
Answer: B
Step-by-step explanation:
Answer:
NO SOLUTION
Step-by-step explanation:
The value of cosines is between -1 and 1
As a result, it will never goes to -12 no matter what
Answer:
y - 6 = (-1/2)(x - 4)
Step-by-step explanation:
As we go from (4, 6) to (6, 10), x (the run) increases by 2 and y (the rise) increases by 4. Thus, the slope of the line connecting these two points is m = rise / run = 4/2 = 2.
The slope of a line perpendicular to this one is the negative reciprocal of 2, which is -1/2.
Using the point-slope formula, we get the following equation for the perpendicular line:
y - 6 = (-1/2)(x - 4) ( obtained using the point (4, 6) )