Find the slope of any line parallel to the line through the given points (3,2),(3,1)
1 answer:
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Solution
Step 1
Write an expression for the area of sector
Where
θ = 52°
π = 3.14
r = 8cm
Step 2
Find the area of the sector after substitution of values into the formula above.
To the nearest tenth the area of the shaded sector of circle C = 29.0cm²
Answer:
(x - 3)² - 16 = 0
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Subtract 7 from both sides
x² - 6x + 7 = 0 ← in standard form
with a = 1, b = - 6
Given a quadratic in standard form then the x- coordinate of the vertex is
= -
= -
= 3
Substitute x = 3 into the equation for y
y = 3² - 6(3) - 7 = 9 - 18 - 7 = - 16 ⇒ (h, k) = (3, - 16)
y = (x - 3)² - 16 = 0