Answer:
b. cosine t less than 0 and cotangent t greater than 0
Step-by-step explanation:
We have the following relation

if we apply the cosine function in the relation we get:


the cosine of t is between 0 and -1 then (cosine t less than 0)
If we now apply cotangent function in the relation:


This means that cotang is greater than 0, therefore the correct answer is b. cosine t less than 0 and cotangent t greater than 0
In the given question,the given explicit formula is

Which is of the form

So the constant difference is 7 here.
Now for the recursive formula
To find the next term, we need to add 7 to the current term, that is

So the correct option is B
25x^2 - 16 = (5x - 4)(5x + 4)
The sum of the terms of a geometric sequence with common ratio lesser than 1 is calculated through the equation,
Sn = (a1) x (1 - r^n) / (1 - r)
Substituting the known values,
S5 = (6) x (1 - (1/3)^5) / (1 - 1/3) = 242/27
Thus, the sum of the first five terms is approximately equal to 8.96.
Answer:
Step-by-step explanation:
Given
The sum of the two positive integer a and b is at least 30, this means the sum of the two positive integer is 30 or greater than 30, so we write the inequalities as below.
The difference of the two integers is at least 10, if b is the greater integer then we subtract integer a from integer b, so we write the inequality as below.
Therefore, the following system of inequalities could represent the values of two positive integers a and b.