Simplify 4a2(a3)/16b(b2)

Kathy distributes jelly beans among her friends. Alia gets 4^2 fewer jelly beans than Kelly, who gets 3^3 jelly beans. How many

pogonyaev

D.

Kelly got 3^3 (27) while Alia got 4^2 (16) less than her. When you put it together you get 3^3 - 4^2

6 0

3 years ago

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Calculate the sample variance and sample standard deviation for the following frequency distribution of heights in centimeters f

Zolol [24]

Answer:

$\bar X = \frac{\sum_{i=1}^n X_i f_i}{n}= \frac{22026.1}{171}=128.81$

$s^2 = \frac{2839948.85- \frac{(22026.1)^2}{171}}{171-1}= 16.59$

$s= \sqrt{16.587}=4.07$

Step-by-step explanation:

For this case we can calculate the sample variance and deviation with the following table

Class Midpoint (Xi) fi Xi*fi Xi^2 *fi

120.6-123.6 122.1 17 2075.7 253443

123.7-126.7 125.2 49 6134.8 768077

126.8-129.8 128.3 29 3720.7 477365.8

129.9-132.9 131.4 41 5387.4 707904.4

133.0-136.0 134.5 35 4007.5 633158.8

___________________________________________

Total 171 22026.1 2839948.85

For this case we can calculate the mean or expected value with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_i f_i}{n}= \frac{22026.1}{171}=128.81$

Now we can calculate the sample variance with the following formula:

$s^2 =\frac{\sum f_i X^2_i -[\frac{(\sum X_i f_i)}{n}]^2}{n-1}$

And if we replace we got:

$s^2 = \frac{2839948.85- \frac{(22026.1)^2}{171}}{171-1}= 16.59$

And the standard deviation would be the square root of the variance and we got:

$s= \sqrt{16.59}=4.07$

7 0

4 years ago

Demi is working on a presentation about a famous mathematician for her math class. She decides to make her poster in the shape o

sukhopar [10]

The question is incomplete. The complete question is:

Demi os working on a representation about a famous mathematician for her math class. She decides to make her poster in the shape of a plus sign. What is the total area of Demi's poster? The image and the measurements of the poster are in the attachment.

Answer: Total area = 1360 square inches

Step-by-step explanation: From the attachment, the poster is formed by two rectangles one over the other and a central part, which is a square. So, the total area is the area of the 2 rectangles minus the area of the square

A = Ar - As

As these forms are regular, the area of both is A = width * length

Area of the 2 rectangle:

width = 20 in

length = 12+20+12 = 44 in

There are 2, then:

Ar = 2.20.44

Ar = 1760

Area of the square:

width = length = 20

As = 20²

As = 400

Total Area:

At = Ar - As

At = 1760 - 400

At = 1360

The total area of the poster is 1360 square inches.

4 0

4 years ago

Solve m+18+23=71 PLZZZZZ I NEED THE ANSER PLZZZ

Aleksandr-060686 [28]

Answer:

m + 18 + 23 = 71

m + 41 = 71

m = 71 - 41

m = 30

8 0

3 years ago

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Estimate 1.9 x 4.4

Sergio039 [100]

Answer:

A

Step-by-step explanation:

it's 8.36 which is between 4 and 10

5 0

3 years ago