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exis [7]
3 years ago
8

During the mayoral election,two debates were held between the canidates. The first debate lasted 1 4/5 hours. The second one las

ted 1 4/5 times as long as the first one. How long was the second debate? Estimate the product. Then find the actual product.
Mathematics
1 answer:
Andrews [41]3 years ago
5 0

Answer:

3\frac {6}{25} hrs \ or \ 3 hrs\  14 mins \ 24 sec

Step-by-step explanation:

The question calls requires one to get the product of the given time. Since first debate lasted for :

1\frac {4}{5} \ hrs

-and the second lasted

1\frac {4}{5} hrs times more than the first then the second took then the first step will involve converting the mixed fractions into improper fraction which will be:

\frac {9}{5}

-Now multiplying

\frac {9}{5}\times\frac{9}{5}\\\\=\frac{81}{25}=3\frac{6}{25}hrs

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rodikova [14]
Jewelery maker has
24 jade beads
30 teak Beads
So we need to find the highest common factor for both 24 and 30
The factors for both numbers are
24 -1,2,3,4,6,8,12,24
30 - 1,2,3,5,6,10,15,30
The highest common factor for both is 6
The greatest number of necklaces she can make is 6
Number of jade beads - 24/6 = 4 jade beads
Number of teak beads - 30/6 = 5 teak beads
So each necklace will have 4 jade beads and 5 teak beads
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3 years ago
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