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Julli [10]
3 years ago
11

Teresa is making iced tea. She has a container that has a volume of 3.95 gallons to store the iced tea.

Mathematics
1 answer:
TEA [102]3 years ago
8 0
Is that the whole question?-
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The radioactive isotope carbon-14 is present in small quantities in all life forms, and it is constantly replenished until the o
Korvikt [17]

Answer:

a) k = 0.000124

b) According to these data, the Shroud of Turin has around 760 years.

Step-by-step explanation:

The amount of carbon-14 is modeled by the following equation:

C(t) = C_{0}e^{-kt}

In which C_{0} is the initial amount and k is the rate of decrease.

(a) Find the value of the constant k in the differential equation.

Half-life of 5595 years.

So C(5595) = 0.5C_{0}

C(t) = C_{0}e^{-kt}

0.5C_{0} = C_{0}e^{-5595k}

e^{-5595k} = 0.5

Applying ln to both sides

-5595k = -0.69

k = 0.000124

b) In 1988 three teams of scientists found that the Shroud of Turin, which was reputed to be the burial cloth of Jesus, contained about 91 percent of the amount of carbon-14 contained in freshly made cloth of the same material. How old is the Shroud of Turin, according to these data?

This is t when C(t) = 0.91C_{0}

C(t) = C_{0}e^{-kt}

0.91C_{0} = C_{0}e^{-0.000124t}

e^{-0.000124t} = 0.91

Applying ln to both sides

-0.000124t = -0.094

t = 760.57

According to these data, the Shroud of Turin has around 760 years.

8 0
4 years ago
Write an expression that evaluates to true if x is non-negative and y is negative?
joja [24]

Answer:

x >= 0 & y<0

x >= 0 means that x is non-negative

y<0 means that y is negative

6 0
2 years ago
Calculate gcd(77, 30) by using the Euclidean algorithm. Find also integers u and v such that 49u + 30v = 1. Furthermore, find su
VladimirAG [237]

Answer:

1. gcd(77,30)=1

77=2*30+17\\30=1*17+13\\17=1*13+4\\13=3*4+1\\4=4*1+0

Since 1 is the last non zero remainder appearing in these equations then, 1 is the gcd of 77 and 30.

2. u=-11, v=18

Using the Euclidean Algorithm we have that

49=1*30+19\\30=1*19+11\\19=1*11+8\\11=1*8+3\\8=2*3+2\\3=1*2+1\\2=1*2+0

Now, we express the remainder as linear combinations of 49 and 30.

1&=3-2\\ &=3-(8-2*3)=3-8+2*3\\&=(11-8)-8+2(11-8)=3*11-4*8\\&=3*11-4(19-11)=7*11-4*19\\&=7(30-19)-4*19=7*30-11*19\\&=7*30-11(49-30)=\\&=18*30-11*49

Then 1=(-11)49+18*30

3. x=18

If 30x\equiv 1\text{mod 77} then

30x=k*77+1 for some k\in \mathbb{Z}.

Then, if k=7,

30x=7*77+1=540\\x=\frac{540}{30}=18

6 0
3 years ago
A website manager has noticed that during the evening​ hours, about 3.23.2 people per minute check out from their shopping cart
aleksandrvk [35]

Answer:

1.  c. Poisson

2. 0.9592 = 95.92% probability that in any one minute at least one purchase is​ made.

3. 0.0017 = 0.17% probability that no one makes a purchase in the next 2​ minutes.

Step-by-step explanation:

We have only the mean, which means that the Poisson distribution is used to solve this question, and thus the answer to question 1 is given by option c.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 3.2 minutes:

This means that \mu = 3.2n, in which n is the number of minutes.

2. What is the probability that in any one minute at least one purchase is​ made?

n = 1, so \mu = 3.2.

This probability is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-3.2}*3.2^{0}}{(0)!} = 0.0408

So

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0408 = 0.9592

0.9592 = 95.92% probability that in any one minute at least one purchase is​ made.

3. What is the probability that no one makes a purchase in the next 2​ minutes?

2 minutes, so n = 2, \mu = 3.2(2) = 6.4

This probability is P(X = 0). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-6.4}*6.4^{0}}{(0)!} = 0.0017

0.0017 = 0.17% probability that no one makes a purchase in the next 2​ minutes.

7 0
3 years ago
What is the distributive property of 364×26
Anna007 [38]
364 \times 26 = \boxed{(360 + 4) \times (20 + 6)} = \boxed{(300 + 64) \times (25 + 1)} = 9464
8 0
4 years ago
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