Answer:
solution given:
B.
CE=2×2=4[base side is double to the line of mid point]
AB=15/2=7.5[b is a mid point]
m<AEC=75°[ corresponding angle]
5.
given:
BD=x+1
CE=x+10
we have
2BD=CE
2(x+1)=x+10
2x+2=x+10
2x-x=10-2
x=8
The answer would be 25/9 as a improper fraction
![\bf \qquad \qquad \textit{Future Value of an ordinary annuity} \\\\ A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Cqquad%20%5Ctextit%7BFuture%20Value%20of%20an%20ordinary%20annuity%7D%0A%5C%5C%5C%5C%0AA%3Dpymnt%5Cleft%5B%20%5Ccfrac%7B%5Cleft%28%201%2B%5Cfrac%7Br%7D%7Bn%7D%20%5Cright%29%5E%7Bnt%7D-1%7D%7B%5Cfrac%7Br%7D%7Bn%7D%7D%20%5Cright%5D)
![\bf A=5280\left[ \cfrac{\left( 1+\frac{0.06}{1} \right)^{1\cdot 4}-1}{\frac{0.06}{1}} \right]](https://tex.z-dn.net/?f=%5Cbf%20A%3D5280%5Cleft%5B%20%5Ccfrac%7B%5Cleft%28%201%2B%5Cfrac%7B0.06%7D%7B1%7D%20%5Cright%29%5E%7B1%5Ccdot%20%204%7D-1%7D%7B%5Cfrac%7B0.06%7D%7B1%7D%7D%20%5Cright%5D)
Joe is making $485 payments monthly, but the amount gets interest on a yearly basis, not monthly, so the amount that yields interest is 485*12
also, keep in mind, we're assuming is compound interest, as opposed to simple interest
E to F = 678.35 miles
F to G = 156.8 miles
G to H = x
Total distance = 2,457 miles
E to G = 678.35 + 156.8 miles
E to G = 835.15
G to H = 2,457 - 835.15
G to H = 1621.85 miles
Answer:
<h2><u>
y = -2x</u></h2>
Step-by-step explanation:
If you notice very carefully then you will see that the line passes through the points :
( 1 , - 2 )
( - 1 , 2 )
Hence the value of x = 1 when the value of y = - 2 .
We know that - 2 × 1 = - 2
⇒ - 2 x = y
⇒ y = - 2x
Hence the first OPTION is correct .
Verification :
For points ( - 1 , 2 ) we can write :
y = - 2x
⇒ 2 = - 2 × - 1
⇒ 2 = 2
Hence the answer is verified .
Always try to use the converse of the graphical method .
( Nothing converse is there ... just saying the opposite steps of that method :P )
I mean in graphical method we plot points and then join , here identify the joined points and then make the equation .
