Slope = rise/run =[y2-y1]/[x2-x1]
1) slope = [90 - 30] / [12 - 4] = 60 / 8 = 15/2
2) slope = [75 - 30] / [10 - 4] = 45 / 6 = 15 / 2
The slopps are equal.
F is odd if and only f f(-x) = -f(x) so f(x) = 0 works because 0 = 0 always.
f is even if and only if f(-x) = f(x) so f(x) = 0 works because there's no x term so nothing changes. 0 = 0.
Answer:
<h3>x = -2</h3>
Step-by-step explanation:
![3[-x + (2 x + 1)] = x -1\\\\\mathrm{Expand\:}3\left(-x+\left(2x+1\right)\right):\quad 3x+3\\3x+3=x-1\\](https://tex.z-dn.net/?f=3%5B-x%20%2B%20%282%20x%20%2B%201%29%5D%20%3D%20x%20-1%5C%5C%5C%5C%5Cmathrm%7BExpand%5C%3A%7D3%5Cleft%28-x%2B%5Cleft%282x%2B1%5Cright%29%5Cright%29%3A%5Cquad%203x%2B3%5C%5C3x%2B3%3Dx-1%5C%5C)
Collect like terms
Add similar elements
If H = 4, we simply plug 4 into the position of h in the expression.
48 + 25 * 4
48 + 100
148
The customer pays $148
Answer:
81.82%
Step-by-step explanation:
Step 1: We make the assumption that 33 is 100% since it is our output value.
Step 2: We next represent the value we seek with $x$x.
Step 3: From step 1, it follows that $100\%=33$100%=33.
Step 4: In the same vein, $x\%=27$x%=27.
Step 5: This gives us a pair of simple equations:
$100\%=33(1)$100%=33(1).
$x\%=27(2)$x%=27(2).
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
$\frac{100\%}{x\%}=\frac{33}{27}$100%x%=3327
Step 7: Taking the inverse (or reciprocal) of both sides yields
$\frac{x\%}{100\%}=\frac{27}{33}$x%100%=2733
$\Rightarrow x=81.82\%$⇒x=81.82%
Therefore, $27$27 is $81.82\%$81.82% of $33$33.
