Ask question

Ask question

All categories

3 years ago

7

42=3(2-3h) can someone plz answer and show me how to do this

1 answer:

maria [59]3 years ago

4 0

You have to use distributive property.<span />

You might be interested in

A triangle with angles of 74° and 16° is?

xxMikexx [17]

The answer is A trust me I did it before

4 0

3 years ago

The ratio of girls to boys in Liza’s classroom is 5

alexira [117]

There are 15 girls in the classroom

6 0

3 years ago

Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo

NikAS [45]

Answer:

$[tex]4608\sqrt{3}$ [/tex]

Step-by-step explanation:

1. $\sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}$

2. $\sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$ <em>factoring 96</em>

<em>since $\sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}$ </em>

3. $\sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

<em>using exponent rule - $(a^{b}) ^{c} = a^{bc}$ </em>

<em> $\sqrt{2^{5} } = 2^{5/2}$ </em>

4. $2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

<em>doing some simple simplification and $4=2^{2}$ and 6=2*3</em>

5. $2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}$

<em>collecting the roots on one side and applying exponent rule</em>

6. $\sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}$

<em>Applying exponents rule on all $\sqrt{3}$ and $\sqrt{2}$ </em>

<em>7. $2^{1/2+1/2+1/2} *2^{5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$ </em>

<em>combining all powers of 2</em>

8. $2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$

<em>Simplifying</em>

9. $2^{9} *3^{2}\sqrt{3}$

10. $512*9\sqrt{3}$

11. $4608\sqrt{3}$

3 0

3 years ago

Read 2 more answers

PicnicTech markets three versions of its Picnic Egg Boxes: the Golden Deluxe, containing 3 gold eggs and one plain egg; the Regu

viktelen [127]

I think im pritty sure its A

4 0

3 years ago

I don't understand this I have spent many points on this same question so this time I will be giving brainliest for the first co

Marrrta [24]

Given:

$|3+4 i|+|3-4 i|+|-3+4 i|+|-3-4 i|$

Solution:

Complex formula:

$|a+b i|=\sqrt{(a+b i)(a-b i)}=\sqrt{a^{2}+b^{2}}$

Let us simplify one by one.

$|3+4 i|=\sqrt{3^{2}+4^{2}}$

$=\sqrt{25}$

|3 + 4i| = 5

$|3-4 i|=\sqrt{3^{2}+(-4)^{2}}$

$=\sqrt{25}$

|3 - 4i| = 5

$|-3+4 i|=\sqrt{(-3)^{2}+4^{2}}$

$=\sqrt{25}$

|-3 + 4i| = 5

$|-3-4 i|=\sqrt{(-3)^{2}+(-4)^{2}}$

$=\sqrt{25}$

|-3 - 4i| = 5

Substitute these in the given expression:

$|3+4 i|+|3-4 i|+|-3+4 i|+|-3-4 i|=5+5+5+5$

$=20$

The solution of the expression is 20.

8 0

3 years ago