Step-by-step explanation:
55 – 5q > 4(7–9)
4(-2)
55- 5q > -8
-5q > -63
q=12.6
Answer:
-6
Step-by-step explanation:
V = 6x + b
1/2 V -3 x = -3
V - 6x = -6
V - 6x = b
Answer: a) An = An-1 + An-2
b) 55ways
Step-by-step explanation:
a) a nickel is 5 cents and a dime is 10cent so a multiple of 5 cents is the possible way to pay the tolls in both choices.
Let An represents the number of possible ways the driver can pay a toll of 5n cents, so that
An = 5n cents
Case 1: Using a nickel for payment which is 5 cents, the number of ways given as;
An-1 = 5( n-1)
Case 2: using a dime which is two 5 cents, the number of ways is given as;
An-2 = 5(n-2)
Summing up the number of ways, we have
An = An-1 + An-2
From the relation,
If n= 0, Ao= 1
n =1, A1= 1
b) 45 cents paid in multiples of 5cents will give us 9 ways(A9)
From the relation, we have that
Ao = 1
A1 = 1
An =An-1 + An-2
Ao = 1
A1 = 1
A2 = A1+Ao = 1+1= 2
A3 = A2 + A1 = 3
A4 = A3+A2=5
A5=A4+A3=8
A6=A5+A4=13
A7 =A6+A5 = 21
A8= A7+A6= 34
A9= A8+A7= 55
So there are 55ways to pay 45cents.
In polynomials, when a term contains both a number and a variable part, the number is called the co-efficient.
In this problem the co-efficient of x =
(8+y)+(3x+y2)
3y+3x+8
Therefore the co efficient of x and y is 3
By segment addition rule AB + BC = AC
3x + 2x - 7 = 2x + 35
3x = 42
x = 1 4
CHECK
3(14) = 42
2(14)-7= 21
-------------------
2(14)+ 35= 63
