50 quarts of 5% butterfat and 1% butterfat milk are to be mixed.
<u>SOLUTION:
</u>
First, I will set up my table. I will fill in the unknowns with variables x and y.
The table is attached below
From the table attached below, we can easily set up the two equations.
<em>Sum of values of two milks = Value of mixture </em>
0.05x + 0.01y = 3
For convenience, we'll multiply the entire equation by 100,
5 x + y = 300 ------> (1)
Now, Sum of amounts of each acid = Amount of mixture
x + y = 100 ---------> (2)
Subtracting equation (2) from (1),
( + ) 5 x + y = 300
( − ) x - y = 100
− − − − − − − −
( = ) 4x + 0y = 200
Thus, 4x = 200
x = 50
Substituting x = 50 in (2),
( 50 ) + y = 100
y = 100 – 50 = 50
hence, 50 quarts of 5% butterfat and 1% butterfat milk are to be mixed.
Answer:
Your 5 changes your slope
Step-by-step explanation:
Answer:
solution
given that
ar=8 __________equation 1
r=4
putting r=4in equation 1 we get
a×4=8
a=2
now
t4=ar^(4-1)
= 2×4^3
=2×4×4×4
=128ans
Answer:
4
Step-by-step explanation:
72-36=36
36÷9=4.........
i hope it can help u!!!!!!!!!!