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Ierofanga [76]
3 years ago
8

In ΔMNO, the measure of ∠O=90°, ON = 65, MO = 72, and NM = 97. What is the value of the tangent of ∠M to the nearest hundredth?

Mathematics
2 answers:
natita [175]3 years ago
5 0

Answer:

what year is this work

Step-by-step explanation:

I don't know sorry. what to help.

Evgen [1.6K]3 years ago
5 0

Answer:

Therefore the value of tangent of ∠m is .9°.

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Please help, show me how to check the answer to this
sveta [45]
3x-7=5x=19
3x-7-5x=5x+19-5x
-2x-7=19
-2x-7+7=19+7
-2x=26
-2x/-2=26/-2
x=-13

:) Did you get that?
5 0
3 years ago
What is the solution to the following system of equations? x+y=5
marta [7]

Answer:

(3,2)

Step-by-step explanation:

Let's solve this via elimination method:

\begin{cases} x+y=5\\x-y=1\end{cases}

By subtracting equation 2 from equation one we obtain:

\begin{cases} x+y=5\\-(x-y=1)\end{cases}\\\\0x+2y=4\\\\y=2

Next we can use any equation either 1 or 2 to determine what x is, I'll use equation 1.  Let y=2 and so:

x+y=5\\\\x+2=5\\x=5-2\\\\x=3

Therefore the solution for the system of equations is:

x=3 and y = 2 as an ordered pair we have (3,2)

7 0
3 years ago
Estimate 12.56+12.69 using front-end estimation.
marissa [1.9K]
<span>12.56+12.69 = 12.60 + 12.70 = 25.30

answer

</span><span>A. about $25.30</span>
5 0
4 years ago
The number of years of education of self-employed individuals in the united states has a population mean of 13.6 years and a pop
muminat

Answer:

0.3 years

Step-by-step explanation:

With problems like these, I always like to start by breaking down the information into smaller pieces.

μ = 13.6

σ = 3.0

Survey of 100 self-employed people

(random variable) X = # of years of education

So now we have some notation, where μ represents population mean and σ represents population standard deviation. Hopefully, you already know that the sample mean of x-bar is the same as the population mean, so x-bar = 13.6. Now, the question asks us what the standard deviation is. Since the sample here is random, we can use the Central Limit Theorem, which allows us to guess that a distribution will be approximately normal for large sample sizes (that is, n ≥ 30). In this case, our sample size is 100, so that is satisfied. We're also told our sample is random, so we're good there, too. Now all we have to do is plug some stuff in.

The Central Limit Theorem says that for large values of n, x-bar follows an approximately normal distribution with sample mean = μ and sample standard deviation = σ/√n. So, with that info, all we need to do to find the standard deviation of x-bar is to plug our σ and n into the above formula.

σ(x-bar) = σ/√n

σ(x-bar) = 3.0/√100

σ(x-bar) = 0.3

So your answer here is .3 years.

7 0
3 years ago
Find the area of a compound shape<br><br> Can you please explain
gtnhenbr [62]

Answer:

A=292.53~m^2

Step-by-step explanation:

<u>Area of a Compound Shape</u>

The shape shown in the image is made of two shapes: Half a circle of radius 8 m and a triangle of base 24 m and height 16 m.

The area of a circle of radius r is:

A_c = \pi r^2

The area of a triangle of base b and height h is:

\displaystyle A_t=\frac{b.h}{2}

Calculate the area of the circle:

A_c = \pi 8^2

A_c = 64\pi

Area of half the circle:

A_c/2 = 32\pi~m^2

Area of the triangle:

\displaystyle A_t=\frac{24\cdot 16}{2}

A_t=192~m^2

The area of the shaded shape is:

A=32\pi~m^2+192~m^2

Substituting the value of pi:

\mathbf{A=292.53~m^2}

4 0
3 years ago
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