Answer: A symbol
Step-by-step explanation: Nothing in that picture gives a value for x
First, you should graph the points. For the first number, called the X-Axis, you should to the right or left, and for the second number, called the Y-Axis, you should go up or down.
To find the distance between Point A and Point C, you should simply just count the number of intersections between them (4).
Angle B is a right angle because if the triangle is bisected at B, it will leave a right angle on either side. Therefore, to label it, you should simply just draw a line through Point B all of the way to line (A,C).
The type of triangle you have drawn is an isosceles, because it has 2 equal angles and 2 equal sides.
We know both of the sides that are unknown will be the same because the triangle is bilateral. Then, we can use the bisection we made earlier to solve for the unknown sides using Pythagorean Theorem. Since earlier, we know the entire bottom is 4, we know half of the bottom is 2. We can also see that the height of the triangle is 2. We then plug those numbers into the Pythagorean Theorem (A^2*B^2=C^2) which makes the value of C^2=16. We then take the square root of C^2 and 16 to see that both unknown sides are 4.
Answer:
1) Equal to 17.4
2)Less than 17.4
Step-by-step explanation:
One thing we must always remember that when we have number 0 after the decimal point, it means we do not need to consider that as it will have no effect on product and on the other operations.
So,
1)
17.4 x 1.0 = 17.4 x 1 = 17.4 (Product is equal to 17.4)
2)
Suppose if a number 'A' which is less than 1 is multiplied by any other number 'B', than the multiplication always result in the number less than B.
For example:
1x0.5 = 0.5 which is less than 1
Similarly for
17.4 x 0.98 = Result will be less than 17.4 as the second number is less than 1.
Product is less than 17.4
Answer:
The answer is 3.618
Step-by-step explanation:
Answer:
Answers in the pics
Step-by-step explanation:
If you have any questions about the way I solved it, don't hesitate to ask me in the comments below ;)
