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3 years ago

Why there is a difference in the time spent per subject.

Mathematics

1 answer:

jeyben [28]3 years ago

6 0

It is based on how challenging the subject is and how much information your learning in it

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Please help me with this question!!!!!

Naddika [18.5K]

Answer:

7/25

Step-by-step explanation:

θ lies in quadrant ii

so 2θ lies in quadrant iv

csc θ=5/3

sin θ=3/5 (sin θ=1/csc θ)

[cos(α+β)=cosαcosβ-sinαsinβ]

cos (2θ)=cos(θ+θ)=cos θ cos θ-sin θ sin θ=cos² θ-sin ²θ=1-sin²θ-sin²θ=1-2sin²θ

=1-2 (3/5)²

=1-2(9/25)

=1-18/25

=(25-18)/25

=7/25

5 0

3 years ago

an initial investment of $9000 grows at an annual interest rate of 5% compounded continuously. how long will it take to double t

tino4ka555 [31]

Answer:

20 years

Step-by-step explanation:

9000/ 100= 900 = 10%

900/2= 450

450 x 2= 900

900 x 10= 9000

Now we multiply 10 by 2 because we doubled the value of our 450 into a 900 and now we get 20.

8 0

3 years ago

How do you write 37/4 as a mixed number

Nataly_w [17]

9/14 the anwser its really easy but i understand

5 0

3 years ago

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Two parallel lines are crossed by a transversal.<br> What is the value of x? <br> ??!!!??!!!!!????

snow_tiger [21]

The answer for this problem: X = 12.

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3 years ago

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To illustrate the effects of driving under the influence (DUI) of alcohol, a police officer brought a DUI simulator to a local h

Oksanka [162]

Answer:

a) If we design the experiment on this way we can check if we have an improvement with the method used.

We assume that we have the same individual and we take a value before with the normal impaired condition and the final condition is the normal case.

b) $-0.96-2.306\frac{0.359}{\sqrt{9}}=-1.24$

$-0.96+2.306\frac{0.359}{\sqrt{9}}=-0.69$

The 95% confidence interval would be given by (-1.24;-0.69)

Step-by-step explanation:

Part a

If we design the experiment on this way we can check if we have an improvement with the method used.

We assume that we have the same individual and we take a value before with the normal impaired condition and the final condition is the normal case.

Part b

For this case first we need to find the differences like this :

Normal, Xi 4.47 4.24 4.58 4.65 4.31 4.80 4.55 5.00 4.79

Impaired, Yi 5.77 5.67 5.51 5.32 5.83 5.49 5.23 5.61 5.6

Let $d_i = Normal -Impaired$

$d_i : -1.3, -1.43, -0.93, -0.67,-1.52, -0.69, -0.68, -0.61, -0.81$

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}=-0.96$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =0.359$

The confidence interval for the mean is given by the following formula:

$\bar d \pm t_{\alpha/2}\frac{s_d}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=9-1=8$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,8)".And we see that $t_{\alpha/2}=2.306$

Now we have everything in order to replace into formula (1):

$-0.96-2.306\frac{0.359}{\sqrt{9}}=-1.24$

$-0.96+2.306\frac{0.359}{\sqrt{9}}=-0.69$

So on this case the 95% confidence interval would be given by (-1.24;-0.69)

6 0

3 years ago