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user100 [1]
3 years ago
12

Answer please I’m like really bad in math hahaha

Mathematics
2 answers:
Naddik [55]3 years ago
7 0

Answer:

2nd

When you flip the x-axis the y-axis becomes negative and the x-axis doesn't change

Step-by-step explanation:

NeTakaya3 years ago
5 0

Answer: I believe the answer is the second one.

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11.4 cm

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Using pythagoras theorem,

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Celine bought 5 leather wallets. If each leather wallet cost $10, how much did Celine spend in all?
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8 0
3 years ago
NUMBER 27 please!!!!!!!
Artist 52 [7]
The inequality can be:
150x \leqslant 3000
Now you divide both sides by 150 to get the #of boxes.

3000 \div 150
Lastly, x is 20. So the maximum amount of boxes that the freight elevator can hold is 20

3 0
3 years ago
The ratio of boys to girls at a movie is 3:4 . If there are 16 girls ​, how many boys are at the​ movie?
Annette [7]

Answer:

12 boys

Step-by-step explanation:

  1. Set up a proportion: \frac{3}{4} = \frac{x}{16}  
  2. Cross multiply, then divide: 3 × 16 = 48, 48 ÷ 4 = 12

I hope this helps!

8 0
3 years ago
Read 2 more answers
We did not find results for: A measure of​ malnutrition, called the​ pelidisi, varies directly as the cube root of a​ person's w
asambeis [7]
\bf \qquad \qquad \textit{double proportional variation}\\\\
\begin{array}{llll}
\textit{\underline{y} varies directly with \underline{x}}\\
\textit{and inversely with \underline{z}}
\end{array}\implies y=\cfrac{kx}{z}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\

\bf \begin{cases}
p=pedalisi\\
w=weight\\
s=\textit{sitting height}
\end{cases}\quad 
\begin{array}{llll}
%pelidisi, varies directly as the cube root of a​ person's weight in grams and inversely as the​ person's sitting height in centimeters.
\textit{pelidisi varies directly}\\
\textit{as cube root of weight}\\
\textit{and inversely to }\\
\textit{sitting height}
\end{array}\implies p=\cfrac{k\sqrt[3]{w}}{s}\\\\
-------------------------------

\bf \textit{we know that }
\begin{cases}
w=48,820\\
s=78.7\\
p=100
\end{cases}\implies 100=\cfrac{k\sqrt[3]{48820}}{78.7}
\\\\\\
100\cdot 78.7=k\sqrt[3]{48820}\implies \cfrac{7870}{\sqrt[3]{48820}}=k
\\\\\\
thus\qquad \boxed{p=\cfrac{\frac{7870}{\sqrt[3]{48820}}\sqrt[3]{w}}{s}}
\\\\\\
\textit{now, what is \underline{p} when }
\begin{cases}
w=54,688\\
s=72.6
\end{cases}?\implies p=\cfrac{\frac{7870}{\sqrt[3]{48820}}\sqrt[3]{54688}}{72.6}

now, if that value is less than 100, then the fellow is "undernourished", otherwise, is overfed.
3 0
3 years ago
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