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-BARSIC- [3]
3 years ago
9

Two pickup trucks each have a mass of 2,000 kg. The gravitational force between the trucks is 3.00 × 10-5 N. One pickup truck is

then loaded with 1,000 kg of bricks. Which of the following would be the new gravitational force between the two trucks?
Physics
1 answer:
levacccp [35]3 years ago
8 0

Answer:

New gravitational force would be: 4.5\,\,\,10^{-5}\,\,\,N

Explanation:

Recall the general form of the gravitational force between two objects of masses m1 and m2 separated a distance "d":

F_g=G\,\frac{m1\,*\, m2}{d^2}

which for the 2000 kg trucks becomes:

F_g=G\,\frac{m1\,*\, m2}{d^2} \\3\,\,\,10^{-5}\,N=G\,\frac{2000\,*\, 2000}{d^2}

when we add 1000 kg of bricks to one truck, we get the following unknown force (x) that we need to find:

F_g=G\,\frac{m1\,*\, m2}{d^2} \\x=G\,\frac{3000\,*\, 2000}{d^2}

Now we divide term by term the last equation by the previous one, in order to cancel out common factors to both equation (G, d^2) and get the following equation:

\frac{x}{3\,\,\,10^{-5}} =\frac{3000}{2000} \\x=\frac{9}{2} \,10^{-5} =4.5\,\,\,10^{-5}\,\,\,N

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mestny [16]

Complete question is;

The frequency and wavelength of EM waves can vary over a wide range of values. Scientists refer to the full range of frequencies that EM radiation can have as the electromagnetic spectrum. Electromagnetic waves are used extensively in modern wireless technology. Many devices are built to emit and/or receive EM waves at a very specific frequency, or within a narrow band of frequencies. Here are some examples followed by their frequencies of operation:

garage door openers: 40.0 MHz

standard cordless phones: 40.0 to 50.0 MHz

baby monitors: 49.0 MHz

FM radio stations: 88.0 to 108 MHz

cell phones: 800 to 900 MHz

Global Positioning System: 1227 to 1575 MHz

microwave ovens: 2450 MHz

wireless internet technology: 2.4 to 2.6 GHz

Which of the following statements correctly describe the various applications listed above? Check all that apply.

a.) All these technologies use radio waves, including low-frequency microwaves.

b.) All these technologies use radio waves, including high-frequency microwaves.

c.) All these technologies use a combination of infrared waves and high-frequency microwaves.

d.) Microwave ovens emit in the same frequency band as some wireless Internet devices.

e.) The radiation emitted by wireless Internet devices has the shortest wavelength of all the technologies listed above.

f.) All these technologies emit waves with a wavelength in the range of 0.10 to 10.0 m.

g.) All the technologies emit waves with a wavelength in the range of 0.01 to 10.0 km.

Answer:

B, D, E, F are the correct statements.

Explanation:

Looking at the options;

A) This is true because radio waves are electromagnetic radiation being used today in television, mobile phones, radios and other areas of communication technologies. And the examples given to us fall in the category of technologies that use radio waves.

B) microwaves usually have long wavelengths and low frequencies. However, sometimes they could have high frequencies usually more than radio waves. Thus, this option is correct.

C) This option is wrong because it's not all the listed technologies that use combination of infrared waves and high-frequency microwaves.

D) we are given the frequency of microwave ovens as 2450 MHz.

Converting to GHz gives; 2.45 GHz.

We are told that wireless internet technology has frequency between 2.4 to 2.6 GHz. Thus, microwave frequency falls in the same range as wireless internet technology and thus the statement is true.

E) we know that wavelength is inversely proportional to frequency. This means that the higher the frequency, the shorter the wavelength.

In the frequencies given to us, wireless internet technology have the highest frequency which means they have the shortest wavelength. The statement is true.

F) from the frequencies given to us, the smallest is garage door openers = 40.0 MHz = 40 × 10^(6) Hz while the biggest is 2.6 GHz = 2.6 × 10^(9) Hz

Formula for wavelength is;

Wavelength = speed of light/frequency

Speed of light = 3 × 10^(8) m/s

Thus;

Wavelength = (3 × 10^(8))/(40 × 10^(6))

Or wavelength = (3 × 10^(8))/(2.6 × 10^(9))

So,wavelength = 7.5 m or 0.12 m

This falls into the given range of 0.10 to 10.0 m.

Thus, the statement is true.

8 0
3 years ago
An aluminium bar 600mm long, with diameter 40mm, has a hole drilled in the center of the bar. The hole is 30mm in diameter and i
arsen [322]

Answer:

Explanation:

l = 600mm = 0.6m

d = 40mm = 0.04m

hd = 30mm = 0.03m (diameter of the hole)

hl = 100mm = 0.1m (hole length)

modulus of elasticity for the aluminium = 85GN/m2

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FromTheMoon [43]
Gravity is pulling everything down . Without it, we all would be floating.
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Liono4ka [1.6K]

Answer:

I=1A

Explanation:

In parallel combination voltage is same

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V=IR

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In R2

V=IR

I=V/R

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I=1A

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jenyasd209 [6]

Answer:

A. independent variable.

Explanation:

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