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Yakvenalex [24]
4 years ago
5

What is the momentum of a 75-kilogram ice skater gliding across the ice at a speed of 13 m/s? ____ kg-m/s

Physics
2 answers:
N76 [4]4 years ago
8 0
P=mv 
p=50kgx5ms-1
p=250
Damm [24]4 years ago
7 0
Momentum = Mass*Velocity

Momentum = 75*13
Momentum = 975

The answer is 975 kg-m/s
Hope you get help
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Answer:

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3 years ago
At what distance is the electrostatic force between two protons equal to the weight of one?.
erik [133]

0.118 m is the distance between the two protons.

Mass of proton = 1.6726 × 10⁻²⁷ kg

Weight of proton= 1.6726 × 10⁻²⁷ x 9.81 N

                            = 1.6408 × 10⁻²⁶ N

Charge of proton = 1.602 × 10⁻²⁹ C

The force between two protons = kq²/r²     where, K is a proportionality    

                                                            constant, q is a charge of proton and  

                                                         r is the distance between two protons.          

                                                       = 9 × 10⁹ × (1.602×10⁻¹⁹)²/r²      

To calculate distance :

  Weight of proton= Force between protons

 ⇒   1.6408 × 10⁻²⁶ N = 9 × 10⁹ × (1.602×10⁻¹⁹)²/r²

 ⇒    r = 0.118m

Therefore, 0.118 m is the distance between the two protons.

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4 0
4 years ago
Read 2 more answers
Sobre un barco, que se mueve en forma rectilínea, y con velocidad constante de 30 [km/h], se mueve un perro en el mismo sentido
almond37 [142]

Answer:

El observador verá correr al perro sobre la cubierta del barco a una velocidad de 40 kilómetros por hora.

Explanation:

Para determinar la velocidad del perro con respecto al observador sentado desde la playa a través del concepto de velocidad relativa, descrito en la siguiente fórmula:

v_{P/B} = v_{P} - v_{B} (1)

Donde:

v_{P/B} - Velocidad del perro relativo al barco, en kilómetros por hora.

v_{P} - Velocidad del perro con respecto al observador, en kilómetros por hora.

v_{B} - Velocidad del barco con respecto al observador, en kilómetros por hora.

Si sabemos que v_{B} = 30\,\frac{km}{h} y v_{P/B} = 10\,\frac{km}{h}, entonces la velocidad del perro con respecto al observador es:

v_{P} = v_{B} + v_{P/B}

v_{P} = 30\,\frac{km}{h} + 10\,\frac{km}{h}

v_{P} = 40\,\frac{km}{h}

El observador verá correr al perro sobre la cubierta del barco a una velocidad de 40 kilómetros por hora.

6 0
3 years ago
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