Answer:
The size of the image is 1.04 m.
Explanation:
Given that,
Height of object = 2.40 m
Distance of object = 2.60 m
Radius of curvature =4.00 m
Focal length
We need to calculate the image distance
Using mirror formula
We need to calculate the height of the image
Using formula of magnification
Put the value into the formula
Hence, The size of the image is 1.04 m
Answer:
The correct answer is:
(a) 84.240 kg
(b) 24.038 m
Explanation:
The given values are:
Force,
F = 81.0 N
Distance,
S = 13.0 m
Time,
t = 5.20 s
As we know,
The acceleration of mass will be:
⇒
On substituting the given values, we get
⇒
⇒
⇒
(a)
The mass of the block will be:
⇒
On substituting the given values, we get
⇒
⇒
(b)
The final velocity after a given time i.e.,
t = 5.00 s
⇒
On substituting the values, we get
⇒
⇒
In time, t = 5.00 s
The distance moved by the block will be:
⇒
On putting the values, we get
⇒
⇒
Answer:
The y-component of the normal force is 45.74 N.
Explanation:
Given that,
Mass of the crate, m = 5 kg
Angle with hill,
We need to find the y component of the normal force. We know that the y component of the normal force is given by :
So, the y-component of the normal force is 45.74 N. Hence, this is the required solution.
Earlier, we stated Newton's first law as “A body at rest remains at rest or, if in motion, remains in motion at constant velocity unless acted on by a net external force.” It can also be stated as “Every body remains in its state of uniform motion in a straight line unless it is compelled to change that state by forces
For example-A stationary object with no outside force will not move. With no outside forces, a moving object will not stop. An astronaut who has their screwdriver knocked into space will see the screwdriver continue on at the same speed and direction forever.
Answer:
i'd say 1kg-----5m-----5kg but im not to sure
Explanation: