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lubasha [3.4K]
3 years ago
6

Solve for the variable (x + 18)° 48°

Mathematics
1 answer:
Mumz [18]3 years ago
6 0

Answer:

=48x+864

Step-by-step explanation:

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Please help! What is the area of this figure?<br><br> Answer and explanation please! &lt;3
andriy [413]

Answer:

19 units²

Step-by-step explanation:

Divide into three shapes:

Large rectangle BEFA

Large triangle - BCE

Small triangle - CDE -

BEFA = 4x3 = 12

BCE = 1/2x4x2 = 4

CDE = 1/2x3x2 = 3

12+4+3=19

6 0
3 years ago
A pipe is leaking at the rate of 16 fluid ounces per minute. Use unit analysis to find out how many gallons the pipe is leaking
larisa [96]

Answer:

The answer is 7.5 gallons per hour.

Step-by-step explanation:

16 fluid ounces multiplied by 60 minutes equals 960 fluid ounces

16 * 60 = 960

960 fluid ounces divided by 128 fluid ounces (which is 1 gallon) equals 7.5 gallons.

960 / 128 + 7.5

So the answer is 7.5 gallons per hour.

Hope this helps! :)

3 0
2 years ago
On a graphing calculator, you can use the function normalcdf(lower bound, upper bound, μ, σ) to find the area under a normal cur
larisa86 [58]

Answer:

99.87% of cans have less than 362 grams of lemonade mix

Step-by-step explanation:

Let the the random variable X denote the amounts of lemonade mix in cans of lemonade mix . The X is normally distributed with a mean of 350 and a standard deviation of 4. We are required to determine the percent of cans that have less than 362 grams of lemonade mix;

We first determine the probability that the amounts of lemonade mix in a can is less than 362 grams;

Pr(X<362)

We calculate the z-score by standardizing the random variable X;

Pr(X<362) = Pr(Z

This probability is equivalent to the area to the left of 3 in a standard normal curve. From the standard normal tables;

Pr(Z<3) = 0.9987

Therefore, 99.87% of cans have less than 362 grams of lemonade mix

4 0
4 years ago
Can someone please help me on this?
Yanka [14]
Tan30=x/18yd
x=0.57734 x 18
x=10.4yd
8 0
4 years ago
Solve the radical equation q-6=√27-2q
rewona [7]

q - 6 = sqrt(27 - 2q)

Squaring both sides:-

(q - 6)^2 = 27 - 2q

q^2 - 12q + 36 = 27 - 2q

q^2 - 10q + 9 = 0

(q - 9)(q - 1) = 0


so there are 2 solutions q = 1 and q = 9.


Testing to see if the solutions are not extraneous:-


q = 9:-

9 - 6 = 3

sqrt(27-18) = 3 So q = 9 is a solution (answer)


q = 1

q - 6 = -5

sqrt (27 - 2) = sqrt 25 = -5 so q = 1 is also an answer

5 0
3 years ago
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