Answer:
The degrees of freedom are given by:
![df = n-1= 26-1=25](https://tex.z-dn.net/?f=%20df%20%3D%20n-1%3D%2026-1%3D25)
And the p value would be:
If we use a 5% of significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 360 second or 6 minutes. We need to be careful since if we use a significance level of 1% the result change
Step-by-step explanation:
Information given
represent the sample mean
represent the sample standard deviation
sample size
represent the value to verify
z would represent the statistic
represent the p value
Hypothesis to test
We want to check if the true mean is at most 360 seconds, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
The statistic for this case would be given by:
(1)
We can replace in formula (1) the info given like this:
The degrees of freedom are given by:
![df = n-1= 26-1=25](https://tex.z-dn.net/?f=%20df%20%3D%20n-1%3D%2026-1%3D25)
And the p value would be:
If we use a 5% of significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 360 second or 6 minutes. We need to be careful since if we use a significance level of 1% the result change