Find the area of each shape and add.Let's start with the first semi-circle(half-circle)
If the area of a circle is πr² , then the area of a semi-circle is 1/2πr² where is 22/7 or 3.14, and r is the radius which is 1.8 meters
A=1/2πr²
A=1/2*22/7*1.8*1.8
A=5.09 m²(rounded to nearest hundredth)
Since the semi-circles are two and have the same radius, multiply the area of the first one by two or go through the same process again.
So 5.09 *2=10.18meters square is the area of the two semi-circles
Now, let's find the area of a rectangle which is length times width, where length is 6 meters and width is (1.8+1.8, because 1.8 is half the width)=3.6 meters
A=l*w
A=6*3.6
A=21.6meters square
Therefore the area of the shape is 10.18m²+21.6m²=219.888m²
Answer:
4
Step-by-step explanation:
Range is the difference between the highest and lowest values of a set of observations
Range = highest value - lowest value
10 - 6 = 4
The number 20 is not a prime number.
Set up a system of equations:
x + y = 0.6
x - y = 7.2
You can solve using elimination. Add the two equations together:
2x + 0y = 7.8
2x = 7.8
x = 3.9
Then plug the number back into either of the two original equations to solve for y:
3.9 + y = 0.6
y = -3.3
The two numbers are 3.9 and -3.3