Answer:
<h2>an+1 = 2×7ⁿ</h2>
Step-by-step explanation:
98÷14
=7
686÷98
=7
4 802÷686
=7
33 614÷4 802
=7
Then the common ratio q for this sequence is 7
recursive formula : an+1 = q×an = ?
an= a1 × qⁿ⁻¹
=2×7ⁿ⁻¹
an+1 = q×an
= 7×(2×7ⁿ⁻¹)
= 2×7ⁿ
B I did this to:) it’s pretty easy once u get the hang of it
You have to find the angle for it try it!!!!!!!!!!
To factor,
<h2>
[[[</h2>
1) First multiply coefficient of a² and constant no,
That is,
3×(-42)=-126
Since the<u> resultant no is negative</u>, you should find two such factors of 126 <u>which</u> <u>will give us the coefficient of a (=11)</u> on subracting those factors.
2) Find the factor
126=2×3×3×7
=18×7
18 and 17 are factors of 126
Also,18-7 =11.
So they are required factors for factoring,
<h2>
]]]</h2>
Once you have understood above steps you can solve on your own. All you need to do is split 11 into factors ,take common terms and you will get answer.
<u>Answer:</u>
3a²+11a-42
=3a²+(18-7)a -42
=3a²+18a-7a-42
=3a(a+6) -7(a+6)
=(a+6)(3a-7)
Answer:
9 and 11
Step-by-step explanation:
So let's say that the first integer is x.
That means that the second integer is x+2, since it us the next odd number.
This problem can be easily solved with our mind the answer is 9 and 11, but I'll show you the steps to slove this.
We make an equation using these two numbers:
Now all we gotta do is solve for x:
Now we use either splitting the middle term or quadratic formula:
Now we split each terma and solve for x:
Now the question states <em>positive </em>so we can rule out x = -11.
Now we have the first integer x = 9,
the second integer is x+2 = 9+2 =11
So the two consecutive positive odd integers are 9 and 11
