Answer:
Let x equal the percentage abundance of one of the two isotopes. The other isotope must then have an abundance of 100 percent minus x percent, which you express in decimal form as (1 - x). For nitrogen, you can set x equal to the abundance of N14 and (1 - x) as the abundance of N15.
Explanation:
Explanation:
To delineate the the nature of the bonds that would be formed between the two elements, let us first write the electronic configuration of the two species;
Be = 2, 2
F = 2, 7
Beryllium is a metal with two valence electrons whereas fluorine is a halogen with seven valence electrons.
When Be loses two electrons it becomes isoelectronic with He;
Be → Be²⁺ + 2e⁻
Also, when fluorine gains an electron, it becomes isoelectronic with Ne;
F + e⁻ → F⁻
This loss and gain of electrons between the two elements creates an electrostatic attraction them and they enter into an electrovalent bond.
Hence;
Be²⁺ + 2F⁻ → BeF₂
7.34 atm
<h3>
Further explanation</h3>
Given:
The Kp for the reaction below is 1.49 · 10⁸ at 100.0°C (a balanced reaction)
In an equilibrium mixture of the three gases.
p CO = p Cl₂ = 2.22 · 10⁻⁴ atm.
Question:
The partial pressure of the product, phosgene (COCl₂), is __ atm.
The Process:
Let us write the equilibrium constant in terms of pressure based on the reaction above.
We set p COCl₂ as the subject to be asked.
Substitute all the data above into the equation.
Thus, the partial pressure of the product, phosgene (COCl₂), is 7.34 atm.
_ _ _ _ _ _ _ _ _ _
Notes:
For the general reactions: ,
the equilibrium constant in terms of concentrations is given by the expression:
<h3>Learn more</h3>
- Write the equilibrium constant for the reaction brainly.com/question/10608589
- Write the equilibrium constant for the reaction of a heterogeneous balance. brainly.com/question/13026406
- What is [S²⁻] at equilibrium? brainly.com/question/12593134