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alexandr1967 [171]
3 years ago
14

What are the two types of ages of rocks?

Chemistry
2 answers:
Ivenika [448]3 years ago
6 0

Answer:

the answer is c just getting over the 20 characters

Alisiya [41]3 years ago
6 0
Answer is C , jajaja
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A silver block, initially at 58.4∘C, is submerged into 100.0 g of water at 25.0∘C in an insulated container. The final temperatu
Vlada [557]

Answer:

The mass of the silver block is 95.52 grams.

Explanation:

Heat lost by silver will be equal to heat gained by the water

-Q_1=Q_2

Mass of silver= m_1

Specific heat capacity of silver = c_1=0.235 J/g^oC

Initial temperature of the silver = T_1=58.4^oC

Final temperature of a silver = T_2=T=26.7^oC=

Q_1=m_1c_1\times (T-T_1)

Mass of water= m_1=100.0 g

Specific heat capacity of water= c_2=4.186 J/g^oC

Initial temperature of the water = T_3=25^oC

Final temperature of water = T_3=T=26.7^oC

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

-(m_1\times 0.235 J/g^oC\times (26.7^oC-58.4^oC))=100.0 g\times 4.186 J/g^oC\times (26.7^oC-25.0^oC)

On substituting all values:

we get, m_1 = 95.52 g

The mass of the silver block is 95.52 grams.

3 0
4 years ago
What is common to all elements in the same group on the periodic table
marin [14]
They all have the same number of electrons.
3 0
3 years ago
Read 2 more answers
In the chemical reaction NaHCO3 + CH3COOH → CH3COONa + H2O +CO2, 83 g of sodium bicarbonate reacts with 70 g of acetic acid. Whi
krok68 [10]
MNaHCO₃: 23+1+12+(48×3) = 84g
mCH₃COOH: 12+(1×3)+12+(16×2)+1 = 60g
.................
84g NaHCO₃ react with 60g CH₃COOH
83g NaHCO₃ react with...........

84g ----- 60g
83g ----- X
X = 59,29g CH₃COOH

We used 70g CH₃COOH, it' too much.
So, acetic acid is excess reagent, and sodium bicarbonate is limiting reagent.
_______________________________
B) Amount of CH3COOH is in excess.

:•)
3 0
4 years ago
Q8. The titration of 15.00 mL of HBr solution of unknown concentration requires 18.44 mL of a 0.100 M KOH solution to reach the
lara [203]

Answer: 0.123 M

Explanation:

According to the neutralization law:

n_1M_1V_1=n_2M_2V_2

where,

M_1 = molarity of HBr solution = ?

V_1 = volume of HBr solution = 15.00 ml

M_2 = molarity of KOH solution = 0.100 M

V_2 = volume of KOH solution = 18.44 ml

n_1 = valency of HBr = 1

n_2 = valency of KOH = 1

1\times M_1\times 15.00=1\times 0.100\times 18.44

M_1=0.123

Therefore, the concentration of the unknown HBr solution is 0.123 M

8 0
3 years ago
Student A pushed on the cart with a force of 500 N. Student B pushed on the other side of the cart. The cart did not move. How m
Nadusha1986 [10]
I depends on the height of the other side of the cart. If it was lower, 400 N. If Higher, at least 600 N. 
5 0
4 years ago
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