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3 years ago

PLEASE HELP WILL GIVE BRAINLIEST!! NEED DONE TODAY PLEASE HELP!!

Mathematics

1 answer:

OlgaM077 [116]3 years ago

3 0

Answer:

They are not traveling at the same speed (Graph attached)

Step-by-step explanation:

(Assuming that the graph and table are the two different cars)

If you look at the graph and the table, you can already see that the value for 8 in the graph is 2, when the value for 8 in the table is 1, meaning that they are not at the same speed.

To graph the table, you need to find the equation first, which is y = 8x because the corresponding value for 1 in the table is 8 and the slope (or the value next to x) is equal to the unit rate, or the value corresponding to 1. Next, you can graph it by finding two points, (0,0) and (1,8), and putting a straight line through them (or use an online graphing calculator).

(Graph is attached)

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mars1129 [50]

What???????? Lol I don’t get it

6 0

2 years ago

Read 2 more answers

What is the slope-intercept form of this equation?

quester [9]

8X+6Y=12

Here's how you solve it:

Just isolate y by itself to get y-intercept form.
This is the formula: Y=MX+B

M is the slope or the number next to X in the original problem.

First:
6Y=-8X+12

Next:
divided everything by 6

Y=-4/3+2

I think the answer is A!

3 0

3 years ago

Read 2 more answers

Write the quadratic equation in standard form and then choose the value of "b." (2x - 1)(x + 5) = 0

Sunny_sXe [5.5K]

If we were to foil
after experieence

we know
ax²+bx+c=0

and
in form
(ax+b)(cx+d)=0
if we expand it, we get
acx²+bcx+adx+bd=0
or
(ac)x²+(bc+ad)x+(bd)=0
compare to
ax²+bx+c=0
we notice that the middle terms (x terms) are

b=(bc+ad)
so

in form
(2x-1)(1x+5)
b=bc+ad=(-1*1+2*5)=-1+10=9

b=9
or you could just expand it

3 0

3 years ago

0.5s +1=7 + 4.5s<br> S =

kvv77 [185]

Answer:

$s = -\frac{3}{2}$

Step-by-step explanation:

Solve for the value of $s$ :

$0.5s + 1 = 7 + 4.5s$

-Combine both $0.5s$ and $4.5s$ by subtracting $0.5s$ by $4.5s$ :

$0.5s + 1 - 4.5s = 7 + 4.5s - 4.5s$

$-4s + 1 = 7$

-Subtract $1$ to both sides:

$-4s + 1 - 1 = 7 - 1$

$-4s = 6$

-Divide both sides by $-4$ :

$\frac{-4s}{-4} = \frac{6}{-4}$

$s = -\frac{3}{2}$

So, the value of $s$ is $-\frac{3}{2}$ .

3 0

3 years ago

Determine the slope of the line that passes through each pair of points.

Soloha48 [4]

$1.)\\\\(5,1) \ \ and \ \ (2,7)\\\\First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \\ \\ m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} } \\ \\m=\frac{ 7-1}{2-5} = \frac{6}{-3}=-2 \\ \\ Use \ point \ form \ of \ a \ line\ with \ one \ point: \\ \\ y-y_{1} =m(x-x _{1}) \\ \\m=-2 , \ \x_{1}=5, \ \ y_{1}=1 \\ \\y-1 = -2(x-5 ) \\\\y=-2x+10+1 \\ \\y=-2x+11$

$2.)\\\\(5,3)\ \ and \ \ (-2,3)\\\\First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \\ \\ m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} } \\ \\m=\frac{ 3-3}{-2-5} = \frac{0}{-7}=0\\ \\ Use \ point \ form \ of \ a \ line\ with \ one \ point: \\ \\ y-y_{1} =m(x-x _{1}) \\ \\m=0 , \ \x_{1}=5, \ \ y_{1}=3 \\ \\y-3 = 0\cdot (x-5 ) \\\\y-3=0 \\ \\y=3$

7 0

3 years ago