To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Write the equation of the lines in slope-intercept form (y=mx+b)
First equation: It is already in slope-intercept form
Second equation: solve y:
Identify the slope of each line:
If two or more lines have the same slope then the lines are parallel
If two lines have slopes that are negative reciprocals then the lines are perpendicular
The two given lines have the same slope: 2/5. Then, they are parallel lines
Answer:
first table shown x and second table shown y function.
Answer:
PV= $40,279.36
Step-by-step explanation:
Giving the following information:
Number of periods= 8*12= 96 months
Interest rate= 0.039/12= 0.00325
Future value (PV)= $55,000
<u>To calculate the initial investment, we need to use the following formula:</u>
PV= FV/(1+i)^n
PV= 55,000 / (1.00325^96)
PV= $40,279.36
Answer:
1) y = 2x-2
2) y = -6/5+1
Step-by-step explanation:
