That which is equivalent to tanθ is A sinθ/cosθ
To answer the question, we need to know what tanθ is
<h3>What is tanθ?</h3>
Tanθ is a trigonometric identity which is the tangent of the angle .
Now, from the unit circle, with radius, r = 1, we have that tanθ = y/x.
Also, the sine of the angle θ is sinθ = x/1 = x
And also, the cosine of the angle θ is cosθ = y/1 = y
Since we have that
- tanθ = y/x,
- sinθ = x and
- cosθ = y
Substituting the values of the variables y and x into tanθ, we have
tanθ = y/x
tanθ = sinθ/cosθ
So, that which is equivalent to tanθ is A sinθ/cosθ
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Answer:
see explanation
Step-by-step explanation:
Check the value of the discriminant
Δ = b² - 4ac
• If b² - 4ac > 0 then roots are real
• If b² - 4ac = 0 roots are real and equal
• If b² - 4ac < 0 then roots are not real
given (x - a)(x - b) = k² ( expand factors )
x² - bx - ax - k² = 0 ( in standard form )
x² + x(- a - b) - k² = 0
with a = 1, b = (- a - b), c = -k²
b² - 4ac = (- a - b)² + 4k²
For a, b, k ∈ R then (- a - b)² ≥ 0 and 4k² ≥ 0
Hence roots of the equation are always real for a, b, k ∈ R
Answer:
y" = -24 / y³
Step-by-step explanation:
6x² + y² = 4
Take the derivative of both sides with respect to x.
12x + 2y y' = 0
Again, take the derivative of both sides with respect to x.
12 + 2y y" + y' (2y') = 0
12 + 2y y" + 2(y')² = 0
Solve for y' in the first equation.
2y y' = -12x
y' = -6x/y
Substitute and solve for y":
12 + 2y y" + 2(-6x/y)² = 0
12 + 2y y" + 2(36x²/y²) = 0
12 + 2y y" + 72x²/y² = 0
6y² + y³ y" + 36x² = 0
y³ y" = -36x² − 6y²
y" = (-36x² − 6y²) / y³
Solve for y² in the original equation and substitute:
y² = 4 − 6x²
y" = (-36x² − 6(4 − 6x²)) / y³
y" = (-36x² − 24 + 36x²) / y³
y" = -24 / y³
X intercept- 3.5
y intercept- 2.5
Answer and Step-by-step explanation:
| \
| \
| \
| \
| \
100 ft. | \
| 2 \
|_________\
x
Use tangent to find the x.
tan(2) = 
Use a calculator to evaluate.
= 2863.6253
So, the boat is 2,863.63 feet from the shore.
#teamtrees #WAP (Water And Plant)
