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3 years ago

Please help.

1 answer:

6 0

3. tan(α) = height/distance
distance = height/tan(α)
distance = (648 m)/tan(13°) ≈ 1399.5 m

6. when y = |x| is translated 6 units down, 6 is subtracted from the y-value:
.. y = |x| -6

10. In point-slope form, the line through point (h, k) with slope m is
.. y -k = m(x -h)
For (h, k) = (10, -9) and m = -2, you have
.. y +9 = -2(x -10)

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From a point at the waters edge, a bridge arch 53 m away has an angle of elevation of 30, and the top of a yacht mast 14 m away

Arte-miy333 [17]

Answer:

Yes

Step-by-step explanation:

We don't even have to do a calculation.

The arch of the bridge is at point C.

The top of the yacht's mast is at E.

Even though the yacht is much closer to the water's edge, its mast has a much smaller angle of elevation.

The yacht can easily pass under the bridge.

3 0

3 years ago

PLS HELP I WILL MARK YOU THE BRAINLEST Graph y>1−3x.

viva [34]

Answer:

Step-by-step explanation: ny line can be graphed using two points. Select two

values, and plug them into the equation to find the corresponding

values.

Graph the line using the slope and the y-intercept, or the points.

Slope:

−

y-intercept:

(

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6 0

2 years ago

Solve the Equations

Vikentia [17]

Answer:

1) -2.13

2) 2.57

3) 33

Step-by-step explanation:

3(8 + 5h) = -28 Distribute the 3

24 + 15h = -28 Subtract 24 from both sides of the equation

15h = -32 Divide both sides by 15 and round

h = - 2.13

19 = 7(3n - 5) Distribute the 7

19 = 21n - 35 Add 35 to both sides of the equation

54 = 21n Divide both sides of the equation by 21

2.57 = n

6s - 7s = -33 Combine the s's

-s = -33 Multiply both sides by -1

s = 33

5 0

1 year ago

You collect 140 total pieces of candy trick or treating and 35 of them are m&m's. What fraction of the candy is not m&m'

tekilochka [14]

$\frac{3}{4}$ of the candy is not m&m's.

Step-by-step explanation:

Given,

Total pieces of candy = 140

Number of m&m's = 35

Fraction = $\frac{Number\ of\ m&m}{Total\ pieces\ of\ candy}$

Fraction = $\frac{35}{140}$

Both 35 and 140 are multiples of 7, therefore,

Fraction of m&m's = $\frac{5}{20} = \frac{1}{4}$

As the number of m&m's fraction and not m&m's fraction will make a total of 1, therefore

fraction of m&m's + fraction of not m&m's = 1

fraction of not m&m's = 1 - fraction of m&m's

fraction of not m&m's = $1-\frac{1}{4}=\frac{4-1}{4}$

fraction of not m&m's = $\frac{3}{4}$

$\frac{3}{4}$ of the candy is not m&m's.

Keywords: fraction, subtraction

Learn more about fractions at:

#LearnwithBrainly

7 0

3 years ago

Help me answer these PLEASE ASAP

Hoochie [10]

Answer:

Answered below

Step-by-step explanation:

Sheet 1: Question 3

Vertically opposite angles are equal so you will equate the angles given,

∠LPN = ∠OPM

7 + 13x = -20 + 16x

27 = 3x

x = 9

Sheet 1: Question 4

Vertically opposite angles are equal so you will equate the angles given,

∠ABD = ∠EBC

2x + 20 = 3x + 15

-x = -5

x = 5

Sheet 1: Question 5

Step 1: Find the value of x

Vertically opposite angles are equal so you will equate the angles given,

∠SOP = ∠ROQ

5x = 4x + 10

x = 10

Step 2: Find angles

Angle SOP = 5x = 5(10) = 50°

Angle ROQ = 50° (because it is vertically opposite to angle SOP)

Angle SOR = 180 - 50 (because all angles on a straight line are equal to 180°)

Angle SOR = 130°

Angle POQ = 130° (because it is vertically opposite to angle SOR)

Sheet 1: Question 6

Angle 1 = 72° (because vertically opposite angles)

∠4 + ∠1 + 41 = 180° (because all angles on a straight line are equal to 180°)

∠4 + 72 + 41 = 180

∠4 = 67°

∠3 = 41° (because vertically opposite angles)

∠2 = 67° (because vertically opposite angles)

Sheet 2: Question 3

Step 1: Find the value of x

Sum of complementary angles is equal to 90°

Angle A + Angle B = 90°

7x + 4 + 4x + 9 = 90°

11x = 90 - 13

11x = 77

x = 7

Step 2: Find angle A and angle B using x

Angle A: 7x + 4

7(7) + 4

Angle A = 53°

Angle B: 4x + 9

4(7) + 9

Angle B = 37°

Sheet 3: Question 3

Step 1: Find the value of x

Sum of supplementary angles is equal to 180°.

Angle A + Angle B = 180°

3x - 7 + 2x + 2 = 180°

5x = 185

x = 37

Step 2: Find angle A and angle B using x

Angle A: 3x - 7

3(37)-7

Angle A = 104°

Angle B: 2x + 2

2(37) + 2

Angle B = 76°

Sheet 3: Question 4

Sum of supplementary angles is equal to 180°.

Step 1: Find x

1/4(36x-8) + 1/2(6x-20) = 180°

Take LCM

[36x - 8 + 2(6x - 20)]/4 = 180°

36x - 8 +12x - 40 = 180 x 4

48x - 48 = 720

48x = 768

x = 16

Step 2: Find both angles with the help of x

Angle 1: 1/4(36x-8)

1/4[36(16)-8] = 568/4

Angle 1 = 142°

Angle 2: 1/2(6x-20)

1/2[6(16)-20] = 76/2

Angle 2 = 38°

Sheet 4: Question 1

All angles on a straight line are equal to 180°

Angle z + 138° = 180°

Angle z = 180 - 138

Angle z = 42°

Sheet 4: Question 2

Linear pair 1: 5 and 7 (because both angles are on a straight line and are equal to 180°)

Linear pair 2: 6 and 8 (because both angles are on a straight line and are equal to 180°)

Sheet 4: Question 3

Step 1: Find the value of x

All angles on a straight line are equal to 180° or linear pairs are equal to 180°

Angle LMO + Angle OMN = 180°

7x + 20 + 10 + 5x = 180°

12x = 180 - 30

x = 150/12

x = 12.5

Step 2: Find angles using the value of x

Angle LMO: 7x + 20

7(12.5) + 20

Angle LMO = 107.5°

Angle OMN: 10 + 5x

10 + 5(12.5)

Angle OMN = 72.5°

Sheet 4: Question 4

Linear pairs are equal to 180°.

Angle 1 + Angle 2 = 180°

1/3(27x-6) + 1/2(6x-20) = 180°

Take LCM = 6

[2(27x-6) + 3(6x-20)]/6 = 180

54x - 12 + 18x - 60 = 1080

72x - 72 = 1080

72x = 1152

x = 16

7 0

3 years ago