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ddd [48]
2 years ago
12

Please help im desperate

Mathematics
2 answers:
Anna35 [415]2 years ago
8 0

Answer:

Step-by-step explanation:

Let s be number of students and a be number of adults.

a + s = 64 -> 5a + 5s = 320

8a + 5s = 461

(8a + 5s) - (5a + 5s) = 461 - 320

3a = 141

a = 47

a + s = 64 -> s + 47 = 64 -> s = 17

Please thank, rate 5, and give brainliest if helpful!

malfutka [58]2 years ago
6 0

Answer:

a + s = 64 -> 5a + 5s = 320

8a + 5s = 461

(8a + 5s) - (5a + 5s) = 461 - 320

3a = 141

a = 47

a + s = 64 -> s + 47 = 64 -> s = 17

give brainliest if helpful!

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3 years ago
Find the sum of first 15 terms of an AP whose 4th and 9th t terms are -15 and -30 respectively.
Serga [27]

Answer:

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Step-by-step explanation:

a + 3d = -15 (1)

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Where,

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n = number of terms

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5d = -15

d = -15/5

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d = -3

Substitute d = -3 into (1)

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Sum of the first 15 terms

S = n/2[2a + (n − 1) × d]

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2 years ago
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2 years ago
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8 0
3 years ago
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