The equation that has only one real number solution is
4a²x²+4abx+ b² = 0 and the solution is x = -b/2a where a, b, and c are real values.
<h3>What is a quadratic equation?</h3>
Any equation of the form Where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
As we know, the formula for the roots of the quadratic equation is given by:
If the quadratic equation has only one solution, then
or
2ax = - b
(2ax+b) = 0
(2ax+b)² = 0 (square on both sides)
Thus, the equation that has only one real number solution is
4a²x²+4abx+ b² = 0 and the solution is x = -b/2a where a, b, and c are real values.
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The line DB is 8cm which is made up of DE and EB which are equal to each other, thus DE and DB are both 4 cm.
Secondly, since AC and DB are perpendicular, that means angle DEC and angle DEA are ninety degrees.
Thus using the Pythagorean theorem, we can find the length of AE and EC which we can add up to find the length of AC.
By adding AE and EC, we get that the length of AE and EC is 7.47 or as approximated to the nearest tenth 7.5.
Hope that helps!
Answer:True
Step-by-step explanation:
-2/3!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
The range is:
{-4, 1, 2, 5, 8}
Step-by-step explanation:
Given the function
- We know that the domain of a function is the set of input or argument values for which the function is real and defined.
As the domain interval -2 ≤ x ≤ 2
i.e. the values in the domain = {-2, -1, 0, 1, 2}
- We also know that the range of a function is the set of values of the dependent variable for which a function is defined.
As the domain interval -2 ≤ x ≤ 2
Putting all the x-values in the domain interval in the function
so
putting x=-2 in the function
putting x=-1 in the function
putting x=0 in the function
putting x=1 in the function
putting x=2 in the function
Thus, when we put the domain values, the corresponding range values are:
x y
-2 -4
-1 1
0 2
1 5
2 8
Therefore, the range is:
{-4, 1, 2, 5, 8}