The probability of the coin getting heads twice is 2/4
Answer:
v=6 or v=8
Step-by-step explanation:
2v^2−(28v−96)=28v−96−(28v−96)
2v^2−28v+96=0
2(v^2-14v+48)
6+8=14 and 6x8=48 so...
2(v−6)(v−8)=0
v−6=0 or v−8=0
v=6 or v=8
<em>Hope this helped and plz mark as brainliest!</em>
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<em>-Luna G.</em>
Answer:
154.3
Step-by-step explanation:
Im NOT sure this is the correct answer but it is the one i found.
Answer:

Step-by-step explanation:
From the information given:
p = x/n
p = 7/10
p = 0.7
sample size n = 15
Suppose X be the number of accidents involved by a single-vehicle.
Then;

Thus, the required probability that at most 4 involve in a single-vehicle is






Answer:
6 years
Step-by-step explanation:
1.75% of 1,200 = 21
so 1 year= 21
21+21= 42 2 years
42+21=63 3 years
63+21=84 4 years
81+21=105 5 years
105+21=126 6 years
Or you can do
21x6=126 so it has to equal 6 years