What is the missing step in this proof

Mathematics

1 answer:

Vilka [71]3 years ago

3 0

The correct answer is letter A

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Can anyone help me solve this is a worksheet extra credit

Crazy boy [7]

Answer:

11. Coordinates of the meeting point 18,24

12.equation for line R, y= -2x/5-4

equation for line E,y=2x/5+12

13. 1,3, 4,5,10,13 ,15

14.70°

15. AC= 47

Step-by-step explanation:

I'm pretty sure about the answers. Please consider making brainliest. Thank you

8 0

3 years ago

Write the equation in slope-intercept form and find the equation of a line through the given point (a) parallel and (b) perpendi

skelet666 [1.2K]

keeping in mind that parallel lines have the same exact slope, hmmm what's the slope of 4x - 2y = 3 anyway? well, let's put it in slope-intercept form firstly.

$\bf 4x-2y=3\implies 4x-3=2y\implies \cfrac{4x-3}{2}=y
\\\\\\
\cfrac{4x}{2}-\cfrac{3}{2}=y\implies \stackrel{slope}{2}x-\cfrac{3}{2}=y$

so we're looking for a line whose slope is 2 and passes through 2,1.

$\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{1})~\hspace{10em}
slope = m\implies 2
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-1=2(x-2)
\\\\\\
y-1=2x-4\implies \blacktriangleright y=2x-3 \blacktriangleleft$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}}
{\stackrel{slope}{2\implies \cfrac{2}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{2}}}
\\\\[-0.35em]
\rule{34em}{0.25pt}$

$\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{1})~\hspace{10em}
slope = m\implies -\cfrac{1}{2}
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-1=-\cfrac{1}{2}(x-2)
\\\\\\
y-1=-\cfrac{1}{2}x+1\implies \blacktriangleright y=-\cfrac{1}{2}x+2 \blacktriangleleft$