Answer:
Step-by-step explanation:
- Rectangle has properties:
- Diagonals are congruent
- Opposite sides are congruent
- All angles are right
<h3>Given</h3>
- m∠ABD = 30°
- AC = 16 in
- BC = ?
<h3>Solution</h3>
<u>As per properties mentioned above we have:</u>
ΔABD is right triangle with ∠B - 30°, ∠A- 90°, ∠D - 60°
Side opposite to 30 is half of the length of the hypotenuse
<u>AD is opposite to ∠B and BD is the hypotenuse, then:</u>
- AD = 1/2*BD
- AD = 1/2(16)
- AD = 8 in
and
Answer:
3
Step-by-step explanation:
9/3=3.11111111 round it and you get 3
Answer:
volume of the solid generated when region R is revolved about the x-axis is π ₀∫^a ( 
x + b )² dx
Step-by-step explanation:
Given the data in the question and as illustrated in the image below;
R is in the region first quadrant with vertices; 0(0,0), A(a,0) and B(0,b)
from the image;
the equation of AB will be;
y-b / b-0 = x-0 / 0-a
(y-b)(0-a) = (b-0)(x-0)
0 - ay -0 + ba = bx - 0 - 0 + 0
-ay + ba = bx
ay = -bx + ba
divide through by a
y = x + ba/a
y = x + b
so R is bounded by y = x + b and y =0, 0 ≤ x ≤ a
The volume of the solid revolving R about x axis is;
dv = Area × thickness
= π( Radius)² dx
= π ( x + b )² dx
V = π ₀∫^a ( x + b )² dx
Therefore, volume of the solid generated when region R is revolved about the x-axis is π ₀∫^a ( x + b )² dx
Answer:
The checkbook balance is $178 .7.
Step-by-step explanation:
As given
Sherry had an ending balance $ 125.36, outstanding deposits of $153.53, and outstanding checks of $100.19.
Thus
Checkbook balance = Ending balance + Outstanding deposits - Outstanding checks
Putting the values in the above
Checkbook balance = $ 125.36 + $153.53 - $100.19
= $ 278.89 - $100.19
= $ 178.7
Therefore the checkbook balance is $178 .7.
Number 6 hopefully it helped
