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zhenek [66]
3 years ago
10

fred has $28 to buy sketch paper for his art class. Each sketch pad costs $9. how many sketch pads can he buy?do not include uni

ts in your answer
Mathematics
1 answer:
Tanzania [10]3 years ago
8 0

Answer:

3

Step-by-step explanation:

9/3=3.11111111 round it and you get 3

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The statements and reasons why the given statements are true are presented in the following two column proofs;

Question 1

Given: 9·(x + 6) - 41 = 75

Prove \ x = \dfrac{62}{9}

Statement                   {} Reason

S1. 9·(x + 6) - 41 = 75   {}  R1. <u>Given</u>

S2. 9·(x + 6)  =  116        {}R2. <u>Addition property</u>

S3. <u>9·x + 54 = 116 </u>         {}R3. Distributive property

S4. 9·x = 62                   {}R4. <u>Subtraction property</u>

S5. x = \dfrac{62}{9}                     {} R5. <u>Division property of equality</u>

Question 2.

Statement                                     {}        Reason

S1. m∠A + m∠B = m∠D   {}                     R1.  Given

S2. ∠C and ∠D form a Linear Pair   {}   R2. Definition of linear pair

S3. ∠C and ∠D are supplementary   {}R3. <u>Linear pair ∠s are supplementary</u>

S4. <u>∠C + ∠D = 180° </u>  {}                           R4. Definition of supplementary

S5. m∠C + m∠A + m∠B = 180°   {}         R5. <u>Substitution property</u>

Question 3.

Statement                                     {} Reason

S1. ∠BDA ≅ ∠A                             {} R1. Given

S2. ∠BDA ≅ ∠CDE                      {}  R2. <u>Vertical angle theorem</u>

S3. ∠CDE ≅ ∠A                      {}       R3. Transitive property of congruency

S4. m∠CDE = m∠A                    {}   R4. <u>Definition of congruency</u>

S5. <u>(13·x + 20)° = (14·x + 15)°</u>      {}   R5. Substitution Property of Equality

S6. 14·x° = 13·x + 5°                       {}R6. <u>Subtraction property</u>

S7. x = 5                      {}                  R7. Subtraction property

Learn more here:

brainly.com/question/11331230

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24 right box VEDR - 6(4)
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Which expression is the best estimate of the product of 7/8 and 1/10
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Multiply across 7/80
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