Question

The product of two number is 20 and the sum of square is 41 find the number​

Answer 1

Let the two number is a and b

so,

product =ab=20

sum of square=$\bold{a^2+b^2=41 }$

Then,

$\bold{(a+b)^2=a^2+b^2+2ab }$

$\bold{ (a+b)^2=41+2×40 }$

$\bold{ (a+b)^2=81 }$

$\bold{a+b=\sqrt{81} }$

$\bold{a+b=9 }$•••••••••(equation I)

Now,

$\bold{(a-b)^2=a^2+b^2-4ab }$

$\bold{ (a-b)^2=41-4×20 }$

$\bold{(a-b)^2=41-40 }$

$\bold{a-b=\sqrt{1} }$

$\bold{a-b=1 }$••••••••(equation II)

Now,combine the equation I and equation II

we,get

$\bold{a+b+a-b=9+1 }$

$\bold{a+\cancel{b}+a\cancel{-b}=10 }$

$\bold{ 2a=10 }$

$\bold{a=\dfrac{10}{2} }$

$\blue{\boxed{ a=5 }}$

Then,

put the value of a in equation II.

we get that,

$\bold{5-b=1 }$

$\bold{b+1=5 }$

$\bold{b=5-1 }$

$\bold{\boxed{\blue{b=4}} }$

so,

The two number is 5 and 4.

Answer 2

Answer:

The numbers are 4 and 5. Their sum = 25 + 16 = 41.

Step-by-step explanation:

Hope this helped :3