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matrenka [14]
3 years ago
9

Help me convert 3/38 into a decimal!

Mathematics
1 answer:
Leya [2.2K]3 years ago
3 0

Answer:

0.07894. . .

Step-by-step explanation:

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A seamstress needs to cut 15 inches pieces of ribbon from a roll of ribbon that is 9 feet in length what is the greatest number
Natali [406]

Answer: 36

Step-by-step explanation:

One roll is of length = 9 feet

1 foot = 12 inches

9 feet = 12 *9 = 108 inches

Since there are 5 rolls

So, total length of 5 rolls = 108 * 5 = 540 inches

Since we are given that A seamstress needs to cut 15-inch pieces of ribbon from a roll of ribbon that is 9 feet in length.

We are supposed to find . What is the greatest number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon

So, number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon:

Hence the greatest number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon is 36

4 0
3 years ago
Help in Circumference of a circle A small pizza has a diameter of 21 cm.
Novay_Z [31]

The circumference of any circle is (pi) x (the diameter of the circle).

The problem gives you both numbers, so all you have to do is multiply them.

Circumference = (pi) x (diameter) = (3.14) x (21cm) = <em>65.94 cm .</em>


3 0
3 years ago
6x+5y+2z=41<br> 4x-10z=-10<br> -x-2y+2z=-1
Rasek [7]
\left[x \right] = \left[ \frac{5\,y}{158}+\frac{6\,z}{79}\right][x]=[​158​​5y​​+​79​​6z​​]
3 0
3 years ago
HELP!!! 10 points marked brainliest!!!! stuck
nexus9112 [7]
Answer: 43
Explanation: All triangles add up to 180. We can subtract angle Z to get 86. Since X and Y are equal, we can divide 86 by 2.
3 0
3 years ago
Find the tenth term of the geometric sequence, given the first term and common ratio.
Natalija [7]

Answer:

a_{10}=\dfrac{1}{128}

Step-by-step explanation:

In the geometric series:

a_1=4\\ \\r=\dfrac{1}{2}

The nth term of the geometric sequence can be calculated using formula

a_n=a_1\cdot r^{n-1}

In your case, n = 10, then

a_{10}\\ \\=4\cdot \left(\dfrac{1}{2}\right)^{10-1}\\ \\=4\cdot \left(\dfrac{1}{2}\right)^9\\ \\=2^2\cdot \dfrac{1}{2^9}\\ \\=\dfrac{1}{2^{9-2}}\\ \\=\dfrac{1}{2^7}\\ \\=\dfrac{1}{128}

8 0
2 years ago
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