Answer:
∠EFG = 48°
Step-by-step explanation:
As FH bisects ∠EFG , ∠EFH = ∠HFG .
We know that ∠EFH = (-5x + 89)° . So ∠HFG = ∠EFH = (-5x + 89)°
Also, ∠HFG + ∠EFH = ∠EFG
=> 2(-5x + 89)° = (61 - x)°
=> -10x + 178 = 61 - x
=> 10x - x = 178 - 61
=> 9x = 117
=> x = 117 / 9 = 13
Putting the value of 'x' in ∠EFG gives :-
(61 - x)° = (61 - 13)° = 48°
The correct answer is x=-2
We have to determine the complete factored form of the given polynomial
.
Let x= -1 in the given polynomial.
So, 
So, by factor theorem
(x+1) is a factor of the given polynomial.
So, dividing the given polynomial by (x+1), we get quotient as
.
So,
= (x+1)
.
= 
=![(x+1)[ 2x(3x-5)-3(3x-5)]](https://tex.z-dn.net/?f=%28x%2B1%29%5B%202x%283x-5%29-3%283x-5%29%5D)
=
is the completely factored form of the given polynomial.
Option D is the correct answer.
Answer:
The value of a is 50°.
Step-by-step explanation:
In an isosceles triangle, 2 sides have the same lengths and same angles so we can assume that the other side of the triangle is 65°.
Given that the total angle of a triangle is 180°, so have to subtract it :



N - 2 = 10n + 4/2
-2 = 9n + 4/2
-4/4 = 9n
-1 = 9n
-9 = n
N is -9.
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