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3 years ago

I need to know the lengths of MN, NP, and PM

Mathematics

2 answers:

andrezito [222]3 years ago

8 0

Answer:

MN = 12 units

NP = 16 units

PM = 20 units

Step-by-step explanation:

You can find MN and NP by counting on the graph. To find PM you will need to use the formula a^2 + b^2 = c^2 ( ^ stands for exponent)

MN and NP will be a and b.

Example: 12^2 + 16^2 = c^2

Simplify.

Example:

144 + 256 = c^2

144 + 256 = 400

Then find the square root of 400 which is 20.

To check your work put all of the sides into the formula and it should be true.

bixtya [17]3 years ago

8 0

MN 12 units
NP 16 units
PM 20 units

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lozanna [386]

Answer:

∠EFG = 48°

Step-by-step explanation:

As FH bisects ∠EFG , ∠EFH = ∠HFG .

We know that ∠EFH = (-5x + 89)° . So ∠HFG = ∠EFH = (-5x + 89)°

Also, ∠HFG + ∠EFH = ∠EFG

=> 2(-5x + 89)° = (61 - x)°

=> -10x + 178 = 61 - x

=> 10x - x = 178 - 61

=> 9x = 117

=> x = 117 / 9 = 13

Putting the value of 'x' in ∠EFG gives :-

(61 - x)° = (61 - 13)° = 48°

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cricket20 [7]

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masya89 [10]

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anastassius [24]

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MakcuM [25]

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