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Ulleksa [173]
4 years ago
9

Simplify. 9(x+3)+15x A. 24x+3 B. 24x+27 C. 9x+27 D. 51x

Mathematics
2 answers:
bonufazy [111]4 years ago
5 0
B. 24x+27. You multiply everything out and add the x's
sergejj [24]4 years ago
5 0
Let's simplify step-by-step.
<span><span>9<span>(<span>x+3</span>)</span></span>+<span>15x
</span></span>Distribute:
<span>=<span><span><span><span>(9)</span><span>(x)</span></span>+<span><span>(9)</span><span>(3)</span></span></span>+<span>15x
</span></span></span><span>=<span><span><span>9x</span>+27</span>+<span>15x
</span></span></span>Combine Like Terms:
<span>=<span><span><span>9x</span>+27</span>+<span>15x
</span></span></span><span>=<span><span>(<span><span>9x</span>+<span>15x</span></span>)</span>+<span>(27)
</span></span></span><span>=<span><span>24x</span>+27
</span></span>Answer:
<span>=<span><span>24x</span>+<span>27
Hope this helps :)</span></span></span>
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Step-by-step explanation:

5 0
3 years ago
120-3/4y=60 solve for y
navik [9.2K]
120 - 3/4y=60
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5 0
4 years ago
Please help. My son and I don't get it
vfiekz [6]
So you have 3 and you want to get rid of 2 2/5. 3-2 is 1  1-2/5 is equal to three fifths, which is the answer. 
6 0
3 years ago
Read 2 more answers
there are n counters in a bag. 4 of the counters are red and the rest are blue. Ross takes a counter from the bag at random and
Ainat [17]

Answer: n = 10.

Step-by-step explanation:

In the bag, we have n counters.

4 of the counters are red.

the rest are blue, then we have:

(n - 4) blue counters.

Now, the probability that Ross takes a blue counter from the bag is equal to the quotient between the number of blue counters (n - 4) and the total number of counters, n

Then the probability is:

p1 = (n - 4)/n

Now he draws another, and it must be blue again, then we can calculate the probability in the same way as above, but he already take a blue counter, so the number of blue counters is (n - 5) and the total number of counters is (n - 1)

The probability of this event is:

p2 = (n - 5)/(n - 1)

The joint probability (the probability that Ross takes two blue counters) is equal to the product of the individual probabilities, and we know that this is equal to 1/3, then we have the equation:

1/3 = ( (n - 4)/n)*((n - 5)/(n - 1))

Now let's solve this for n.

n*(n - 1)/3 = (n - 4)*(n - 5)

(n^2 - n)/3 = n^2 - 4*n - 5*n + 20

n^2 - n = 3*(n^2 - 9*n + 20)

n^2 - n = 3*n^2 - 27*n + 60

0 = (3*n^2 - n^2) - 27*n + n + 60

0 = 2*n^2 - 26*n + 60

The two solutions of this equation can be found with Bhaskara's equation:

n = \frac{-(-26) +- \sqrt{(-26)^2 - 4*2*60} }{2*2} = \frac{26+- 14}{4}

Then the two solutions are:

n = (26 - 14)/4 = 3

This is not an option, because we know for sure that we have 4 red counters, then this option can be discarded.

The other solution is:

n = (26 + 14)/4 = 40/4 = 10

Then we have n = 10, 10 counters in total.

4 0
3 years ago
Multiply  (x+y-3)(x+y+3)=____
vfiekz [6]
(x+y-3)(x+y+3) = x^2+xy+3x+xy+y^2+3y-3x-3y-9 = -9+x^2+y^2+2xy
8 0
3 years ago
Read 2 more answers
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