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svetlana [45]
2 years ago
14

Partes de la ventana principal de Microsoft excel 2013 con sus respectivas funciones

Computers and Technology
1 answer:
Murljashka [212]2 years ago
5 0

Answer:

es 1986 de ventana indese ya layse me gane cinco

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6 0
3 years ago
If 209g of ethanol are used up in a combustion process, calculator the volume of oxygen used for the combustion at stp​
SOVA2 [1]

Answer:

a) The volume of oxygen used for combustion at STP is approximately 305 dm³

b) The volume of gas released during combustion at STP is approximately 508 dm³

Explanation:

The given chemical reaction equation for the burning of ethanol in air, is presented as follows;

2CH₃CH₂OH (l) + 6O₂ (g) → 4CO₂ (g) + 6H₂O

The mass of ethanol used up in the combustion process, m = 209 g

The molar mass of ethanol, MM = 46.06844 g/mol∴

The number of moles of ethanol in the reaction, n = m/MM

∴ n = 209 g/(46.06844 g/mol) ≈ 4.537 moles

a) Given that 2 moles of ethanol, CH₃CH₂OH reacts with 6 moles of oxygen gas molecules, O₂, 4.54 moles of ethanol will react with (6/2) × 4.537 = 13.611  moles of oxygen

The volume occupied by one mole os gas at STP = 22.4 dm³

The volume occupied by the 13.611 moles of oxygen gas at STP, 'V', is given as follows;

V = 13.611 mol × 22.4 dm³/mole = 304.8864 dm³ ≈ 305 dm³

The volume occupied by the 13.611 moles of oxygen gas at STP, V = The volume of oxygen used for the combustion ≈ 305 dm³

b) The total number of moles of gases released in the reaction, is given as follows;

The total number of moles = (4.537/2) × (4 + 6) = 22.685 moles of gas

The total volume of gas released, V_T = The volume of gas released during the combustion at STP = 22.685 moles × 22.4 dm³/mole = 508.144 dm³ ≈ 508 dm³

7 0
3 years ago
In every organization, workers receive and sendinformation daily. The flow of this information should be____________.upward and
Aleks [24]

Answer:

upward and downward

Explanation:

4 0
3 years ago
Which button will allow you to insert quotes and notes into text into a document​
oksano4ka [1.4K]

Answer:

You copy and paste it

Explanation:

right click on the mouse then it will say copy, you right click on the mouse and click paste voila! it works! (If you're using word there are 3 options for pasting, Keep source formatting, Merge formatting and keep text only)

8 0
3 years ago
Question 1:
Julli [10]

Answer:

Following are the code to the given question:

#include<iostream>//header file

#include<math.h>//header file

using namespace std;

int main()//main method

{

   long long x, x1, y, y1;//defining long variable

   int count=0,i,j;//defining integer variable

   cout<<"Enter a range for x coordinates: "<<endl;//print message        

   cin>>x>>x1;//input x and x1 value                          

   cout<<"Enter a range for y coordinates: "<<endl;//print message

   cin>>y>>y1; //input y and y1 value  

   for(i = x; i <= -x1; i++)//use nested loop that tests each coordinates                                        

   {

       for(j = y; j <= y1; j++)//use nested loop that tests each coordinates

       {

           if(((2*pow(i,2)) + abs(2*i*j) + pow(j,2)) == 10000)//use if that checks condition as per the given question

           {

               cout<<"There is a planet at "<<i<<", "<<j<<endl;//  print coordinates

               count++;//incrementing count variable value                                                    

           }

       }

   }

   cout<<"Total number of planets detected are: "<<count<<endl;//print count value

   return 0;

}

Explanation:

In this code, inside the main method long "x, x1, y, and y1" and integer "count, i, and j" type variable is declared that uses a long variable to input value from the user-end.

In the next step, two nested loops have defined that test each coordinate and define if block that checks condition as per the given question and use i, j, and count variable to print value with the message.

3 0
3 years ago
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