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olya-2409 [2.1K]
3 years ago
13

Which diagram is used as a popular technique for investigating causes and effects? 1. Cause and effect 2. Fishbone/lshikawa 3. R

oot course 4. Fact finding
Computers and Technology
1 answer:
pishuonlain [190]3 years ago
8 0

Answer: 2)Fishbone/lshikawa

Explanation: Fishbone diagrams are those diagrams which help in the identification of the problem causing factors and reasons behind.This diagrams find the roots of the problem to solve it. Fishbone diagram is also known as the Ishikawa diagram.

The other given options are incorrect because they are not any technique for finding the roots of the problem.Thus, the correct option is option(2).

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Write a program in C which will open a text file named Story.txt. You can create the file using any text editor like notepad etc
ddd [48]

Answer:

See explaination

Explanation:

#include <stdio.h>

#include <stdlib.h>

int main()

{

FILE * file_object;

char file_name[100];

char ch;

int characters=0, words=0;

printf("Enter source file name: ");

scanf("%s", file_name); //asking user to enter the file name

file_object = fopen(file_name, "r"); //open file in read mode

if (file_object == NULL)

{

printf("\nUnable to open file.file not exist\n"); //check if the file is present or not

}

while ((ch = fgetc(file_object)) != EOF) //read each character till the end of the file

{

if (ch == ' ' || ch == '\t' || ch == '\n' || ch == '\0') //if character is space or tab or new line or null character increment word count

words++;

else

characters++; //else increment character count this assures that there is no spaces count

}

printf("The file story.txt has the following Statistics:\n"); //finally print the final statistics

if (characters > 0)

{

printf("Words: %d\n", words+1); //for last word purpose just increment the count of words

printf("Characters (no spaces): %d\n", characters);

}

fclose(file_object); //close the file object

return 0;

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6 0
3 years ago
Determine whether or not the following pairs of predicates are unifiable. If they are, give the most-general unifier and show th
Evgen [1.6K]

Answer:

a) P(B,A,B), P(x,y,z)

=> P(B,A,B) , P(B,A,B}  

Hence, most general unifier = {x/B , y/A , z/B }.

b. P(x,x), Q(A,A)  

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q.

c. Older(Father(y),y), Older(Father(x),John)

Thus , mgu ={ y/x , x/John }.

d) Q(G(y,z),G(z,y)), Q(G(x,x),G(A,B))

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))  

This is not unifiable as x cannot be bound for both A and B.

e) P(f(x), x, g(x)), P(f(y), A, z)    

=> P(f(A), A, g(A)), P(f(A), A, g(A))  

Thus , mgu = {x/y, z/y , y/A }.

Explanation:  

Unification: Any substitution that makes two expressions equal is called a unifier.  

a) P(B,A,B), P(x,y,z)  

Use { x/B}  

=> P(B,A,B) , P(B,y,z)  

Now use {y/A}  

=> P(B,A,B) , P(B,A,z)  

Now, use {z/B}  

=> P(B,A,B) , P(B,A,B}  

Hence, most general unifier = {x/B , y/A , z/B }  

b. P(x,x), Q(A,A)  

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q  

c. Older(Father(y),y), Older(Father(x),John)  

Use {y/x}  

=> Older(Father(x),x), Older(Father(x),John)  

Now use { x/John }  

=> Older(Father(John), John), Older(Father(John), John)  

Thus , mgu ={ y/x , x/John }  

d) Q(G(y,z),G(z,y)), Q(G(x,x),G(A,B))  

Use { y/x }  

=> Q(G(x,z),G(z,x)), Q(G(x,x),G(A,B))

Use {z/x}  

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))  

This is not unifiable as x cannot be bound for both A and B  

e) P(f(x), x, g(x)), P(f(y), A, z)  

Use {x/y}  

=> P(f(y), y, g(y)), P(f(y), A, z)  

Now use {z/g(y)}  

P(f(y), y, g(y)), P(f(y), A, g(y))  

Now use {y/A}  

=> P(f(A), A, g(A)), P(f(A), A, g(A))  

Thus , mgu = {x/y, z/y , y/A }.

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