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2 years ago

Series calcular s=1+2+3+....+86

Mathematics

1 answer:

qwelly [4]2 years ago

6 0

Answer:

S = 3741

Step-by-step explanation:

Here, we want to calculate the sum of the first 86 numbers (starting from 1)

Mathematically, we can use the formula;

Sn = n/2[ a + L]

Where n is the number of terms (86 here)

a is the first term which is 1 and L is the last term which is 86

So, we have the sum as;

Sn = 86/2(1 + 86) = 43 * 87 = 3741

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Marizza181 [45]

i would say B

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3 years ago

A line has a slope of -6 over 7. What is the slope of the line parallel to it? And what is the slope of the line perpendicular t

olga_2 [115]

The slope of the parallel line is -6/7
the slope of the perpendicular line is 7/6
the slope of the line = -6/7
the gradient of two parallel lines are equal
the product of the gradient of two perpendicular lines is -1
: the gradient m1*m2 = -1
m2= -1(-6/7)
m2= 7/6

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3 years ago

Expanding triple brackets, i will give brainliest

rewona [7]

Answer:

${x}^{3} + {x}^{2} −24x+36$

Step-by-step explanation:

$(x + 6)(x - 2)(x - 3)$

$[x(x−2)+6(x−2)](x−3)$

$( {x}^{2} −2x+6x−12)(x−3)$

$( {x}^{2} +4x−12)(x−3)$

${x}^{3} + {x}^{2} −24x+36$

<h3>Hope it is helpful....</h3>

4 0

2 years ago

What’s the missing side length?

qaws [65]

4 yd. 9-5=4. Hope this helps!

5 0

2 years ago

Can I get some help please? <br><br><br> Thanks!

quester [9]

An ellipse (oval shape) is expressed by the following equation:

$\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2}=1$ where h is the x coordinate of the center and k is the y coordinate of the center. Furthermore, a is the horizontal distance from the center, and b is the vertical distance from the center. Lastly, c is the distance from the center to one of the foci (they are spaced apart equally).

We can find the foci by using $a^2 - b^2 = c^2$

36 - 11 = $c^2$

$c = \sqrt{25} = 5$

Since the k value in this case is 0, the y value of both foci are 0. Also, since h and k are both 0, we know the center of the ellipse is at the origin.

So the foci are (-5, 0) and (5, 0)

Hope this helps :)

3 0

3 years ago