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lys-0071 [83]
3 years ago
8

What is the slope of the line shown below?

Mathematics
1 answer:
Anton [14]3 years ago
8 0

Answer:

Slope = 3

Step-by-step explanation:

2 - 8 = -6

2 - 4 = -2

Slope = 3

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Find the squares of (m-1)​
Alchen [17]

Answer:

Solution

verified

Verified by Toppr

m

2

−3m−1=0

m

2

−3m=1 → (1)

Third term =(

2

1

coeeficientofm)

2

(

2

1

×(−3))

2

=(

2

−3

)

2

=

4

9

Adding

4

9

to both sides of equation (1), we get

m

2

−3m+

4

9

=1+

4

9

∴ m

2

−3m+

4

9

=

4

4+9

∴ (m−

2

3

)

2

=

4

13

Taking square roots on both sides

∴ m−

2

3

=±

2

13

∴ m=

2

3

+

2

13

or m=

2

3

−

2

13

m=

2

3+

13

,

2

3−

13

are the roots of the given quadratic equation.

8 0
2 years ago
What is an imaginary number?
trapecia [35]

An imaginary number is a complex number that can be written as a real number multiplied by the imaginary unit i, which is defined by it's property i² = −1. The square of an imaginary number bi is −b². For example, 5i is an imaginary number, and it's square is −25.

8 0
3 years ago
Five less then 3 times a number is 3 let x be unknown <br> number
azamat

Answer:

3x-5=3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Please help me with these problems Thank You so much!
Radda [10]
Where r the problems
8 0
3 years ago
In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample. To determine
zimovet [89]

Answer:

(a)  0.2650

(b)  0.0111

(c)  0.0105

(d)  0.0006

Step-by-step explanation:

Given that:

In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample.

Suppose that the number of CFUs that appear after incubation follows a Poisson distribution with mean μ = 15.       &;

If the area of the agar plate is 75cm²;

what is the probability  of observing fewer than 4 CFUs in a 25 cm² area of the plate.

We can determine the mean number of CFUs that appear on a 25cm² area of the plate as follows;

75cm²/25cm² = 3

Since;

mean  μ = 15  

mean number of CFUs that appear on a 25cm² = 15/3 = 5 CFUs

Thus ; the probability of observing fewer than 4 CFUs in a 25 cm² area of the plate is estimated as:

= P(X < 4)

Using the EXCEL FUNCTION ( = poisson.dist(3, 5, TRUE) )

we have ;

P(X < 4) = 0.2650

b) If you were to count the total number of CFUs in 5 plates, what is the probability you would observe more than 95 CFUs?

Given that the total number of CFUs = 5 plates; then the mean number of CFUs in 5 plates =  15×5 = 75 CFUs

The probability is therefore = P( X > 95 )

= 1 - P(X ≤ 95)

= 1 - poisson.dist(95,75,TRUE) ( by using the excel function)

= 0.0111

c) Repeat the probability calculation in part (b) but now use the normal approximation.

Let assume that the mean and the variance of the poisson distribution are equal

Then;

X \sim N (\mu = 75 , \sigma^2 = 75)

We are to repeated the probability calculation in part (b) from above;

So:

P( X > 95 )

use the normal approximation

From standard normal variable table:

P(Z > 2.3094)

Using normal table

P(Z > 2.3094) = 0.0105

(d)  Find the difference between this value and your answer in part (b).

So;

the difference between the value in part c and part b is;

=  0.0111 - 0.0105

= 6*10^{-4}

= 0.0006 to four decimal places

5 0
4 years ago
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