Answer:
|F net| = 20.22 N
θ ≈ 19.8°
Step-by-step explanation:
F net = 15N i + 8cos(60°)N i + 8sin(60°)N j
= 15N i + 8×½N i + 8×√3/2N j
= 15N i + 4N i + 4√3N j
= 19N i + 4√3N j
|F net| = √(19²+(4√3)²) = √(361+48) = √409 ≈ 20.22N
tan(θ) = 4√3 ÷ 19 ≈ 0.36 → θ ≈ arctan(0.36) = 19.8°
Answer:
Option D
Step-by-step explanation:
f(x) =
Transformed form of the function 'f' is 'g'.
g(x) = 
Property of vertical stretch or compression of a function,
k(x) = x
Transformed function → m(x) = kx
Here, k = scale factor
1). If k > 1, function is vertically stretched.
2). If 0 < k < 1, function is vertically compressed.
From the given functions, k = 
Since, k is between 0 and
, function f(x) is vertically compressed by a scale factor
.
g(x) = f(x + 4) represents a shift of function 'f' by 4 units left.
g(x) = f(x - 4) represents a shift of function 'f' by 4 units right.
g(x) = 
Therefore, function f(x) has been shifted by 4 units left to form image function g(x).
Option D is the answer.
<span>x − y ≥ 3 ... > stands for above on a graph, and the line under it _ stands for shaded.</span>
X + Y + Z = 8
2x = Z - 2
X + Z = 5
X = 1
1 + Y + Z = 8
Y + Z = 6
1 + Z = 5
Z = 4
1 + Y + 4 = 8
5 + Y = 8
Y = 3
The variables are 1, 3, 4.
46+19+54= 119, so the answer is 119