All categories

2 years ago

Fiona loves pizza. She ate of a pizza for dinner one night. She ordered another pizza the

1 answer:

4 0

$\stackrel{1st~night}{\cfrac{5}{6}}+\stackrel{\textit{2nd night}}{\cfrac{1}{3} }\implies \cfrac{(1)5~~ +~~(2)1}{\underset{\textit{using this LCD}}{6}}\implies \cfrac{7}{6}\implies 1\frac{1}{6}$

You might be interested in

What is a polyhedral?

Naily [24]

A polyhedral is a shape that is flat and that has straight sides.

3 0

3 years ago

Read 2 more answers

Help ASAP

krok68 [10]

Answer:

1. x=10,-10

2. x = 5

x = -5

3. x=-5

4. x ∈ {4,- 3/2}

Step-by-step explanation:

7 0

3 years ago

Find a solution to the system. Make sure to write as a coordinate.

RUDIKE [14]

Answer:

x=2, y=3

Step-by-step explanation:

This is a system of equations.

To solve a system of equations, we use the substitution method.

We can plug in the first equation, $x=2y-4$ , into the value for x in the second equation. Now, the second equation looks like this:

$2*(2y-4)+y=7$

We simplify and solve for y:

→ $4y-8+y=7$

→ $5y=15$

→ $y=3$

Now, we plug in the value for y, which is 3, into either equation. I will just use the first equation:

→ $x=2*3-4$

→ $x = 2$

Let me know if my explanation is unclear.

3 0

3 years ago

The length of a rectangle is increasing at a rate of 4 meters per day and the width is increasing at a rate of 1 meter per day.

puteri [66]

Answer:

$\displaystyle \frac{dA}{dt} = 102 \ m^2/day$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Geometry

Area of a Rectangle: A = lw

l is length
w is width

Calculus

Derivatives

Derivative Notation

Implicit Differentiation

Differentiation with respect to time

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

$\displaystyle l = 10 \ meters$

$\displaystyle \frac{dl}{dt} = 4 \ m/day$

$\displaystyle w = 23 \ meters$

$\displaystyle \frac{dw}{dt} = 1 \ m/day$

Step 2: Differentiate

[Area of Rectangle] Product Rule: $\displaystyle \frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}$

Step 3: Solve

[Rate] Substitute in variables [Derivative]: $\displaystyle \frac{dA}{dt} = (10 \ m)(1 \ m/day) + (23 \ m)(4 \ m/day)$
[Rate] Multiply: $\displaystyle \frac{dA}{dt} = 10 \ m^2/day + 92 \ m^2/day$
[Rate] Add: $\displaystyle \frac{dA}{dt} = 102 \ m^2/day$