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3 years ago

9

Fiona loves pizza. She ate of a pizza for dinner one night. She ordered another pizza the

1 answer:

kvv77 [185]3 years ago

4 0

$\stackrel{1st~night}{\cfrac{5}{6}}+\stackrel{\textit{2nd night}}{\cfrac{1}{3} }\implies \cfrac{(1)5~~ +~~(2)1}{\underset{\textit{using this LCD}}{6}}\implies \cfrac{7}{6}\implies 1\frac{1}{6}$

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Maurice read 10 pages that is 50 percent of the paper lenght what i the paper lenght

Natali5045456 [20]

Answer:

Would it not be 20?

Step-by-step explanation:

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3 years ago

PLSS ANSWER TIHS <br> 153 X 15 =

Sonja [21]

The answer for 153 X 15 is 2,295!

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2 years ago

Find Mx, My, and (x, y) for the lamina of uniform density rho bounded by the graphs of the equations. y = x2/3, y = 0, x = 1

erik [133]

Answer:

$\mathbf{(\overline x , \overline y ) = (\dfrac{5}{8}, \dfrac{5}{14})}$

Step-by-step explanation:

Given that:

$y = x^{2/3}$ at y = 0 , x = 1

Then:

Area = $\int^{1}_{0} x^{2/3} \ dx$

Area = $\begin {bmatrix} \dfrac{3}{5}x^{5/3} \end {bmatrix} ^1_0$

Area = $\dfrac{3}{5}$

Then:

$\overline x = \dfrac{1}{A} \int^b_a x (f(x) -g(x) ) \ dx$

$\overline x = \dfrac{5}{3} \int^1_0 x (x^{2/3} -0 ) \ dx$

$\overline x = \dfrac{5}{3} \int^1_0 x^{5/3} \ dx$

$\overline x = \dfrac{5}{3} \ [\dfrac{3}{8}x^{8/3}]^1_0$

$\overline x = \dfrac{5}{3} \times \dfrac{3}{8}$

$\overline x = \dfrac{5}{8}$

Similarly;

$\overline y = \dfrac{1}{A} \int^b_a \dfrac{1}{2} \begin{bmatrix} (f(x)^)2 - (g(x))^2 \end {bmatrix} \ dx$

$\overline y = \dfrac{5}{3} \int^1_0 \dfrac{1}{2} \begin{bmatrix} (f(x^{2/3})^2 -0 \end {bmatrix} \ dx$

$\overline y = \dfrac{5}{3} \int^1_0 \dfrac{1}{2} \begin{bmatrix} (x^{4/3} ) \end {bmatrix} \ dx$

$\overline y = \dfrac{5}{3} \begin{bmatrix} \dfrac{1}{2} (x^{7/3} ) \times \dfrac{3}{7} \end {bmatrix} ^1_0$

$\overline y = \dfrac{5}{3} \begin{bmatrix} \dfrac{3}{14} (x^{7/3} ) \end {bmatrix} ^1_0$

$\overline y = (\dfrac{5}{3} \times \dfrac{3}{14} )$

$\overline y = \dfrac{5}{14}$

Thus; $\mathbf{(\overline x , \overline y ) = (\dfrac{5}{8}, \dfrac{5}{14})}$

4 0

3 years ago

Solve. <br> 1/2x - 2/5x = -2

Makovka662 [10]

1/2x - 2/5x = -2

1/10x = -2

x = -20

3 0

3 years ago

Find the area of the following polygons:<br> Given: AC = 12, AD = 16

Kisachek [45]

38 is the correct answer

6 0

3 years ago

Read 2 more answers