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Morgarella [4.7K]
3 years ago
8

I need help with this​

Mathematics
1 answer:
WARRIOR [948]3 years ago
3 0

Answer:

Is the question or is there more??

Step-by-step explanation:

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Please answer the question in the picture below. Thanks!
Arada [10]

Answer:

Yes

Step-by-step explanation:

\frac{DH}{HE}=\frac{18}{36}=\frac{1}{2}

\text{This means that } DH=\frac{1}{2}HE

and thus the given segments are parallel by the converse of the triangle proportionality theorem.

4 0
2 years ago
True false test consists of 10 questions how many ways can a student mark one answer to each answer
ololo11 [35]
2^10 = 1024 possible ways to answer the test
8 0
3 years ago
Dew help me please come on
adell [148]

Answer:

75c-180

420 for 8 customers

Step-by-step explanation:

Her tools cost her 180

-180

she makes 75 per customer

75c

She will make

75c-180

She gets 8 customers

75(8)-180

600-180

420

7 0
3 years ago
Find the area of the shaded portion in the equilateral triangle with sides 6.
LUCKY_DIMON [66]
Triangle is equilateral with sides of 6.
Therefore all angles = 60°
Ht of 30-60-90 is 3sr3 = 5.196
Area of 30-60-90 = 1/2×b×h = 3×5.196
Area = 15.59
Pie slice from each corner = 60/360×pi×r^2, with r = 3
1/6×pi×9 = 4.71 × 3 pie slices = 14.13
So, shaded inner region = area triangle - 3 pie corners = 15.59-14.13
= 1.46
7 0
3 years ago
Triangles DEF and D'E'F' are shown on the coordinate plane below: . . Triangle DEF and triangle D prime E prime F prime with ord
Brilliant_brown [7]
<span><u><em>The correct answer is:</em></u>
180</span>°<span> rotation.

<u><em>Explanation: </em></u>
<span>Comparing the points D, E and F to D', E' and F', we see that the x- and y-coordinates of each <u>have been negated</u>, but they are still <u>in the same position in the ordered pair. </u>

 <u>A 90</u></span></span><u>°</u><span><span><u> rotation counterclockwise</u> will take coordinates (x, y) and map them to (-y, x), negating the y-coordinate and swapping the x- and y-coordinates.

<u> A 90</u></span></span><u>°</u><span><span><u> rotation clockwise</u> will map coordinates (x, y) to (y, -x), negating the x-coordinate and swapping the x- and y-coordinates.

Performing either of these would leave our image with a coordinate that needs negated, as well as needing to swap the coordinates back around. 

This means we would have to perform <u>the same rotation again</u>; if we began with 90</span></span>°<span><span> clockwise, we would rotate 90 degrees clockwise again; if we began with 90</span></span>°<span><span> counter-clockwise, we would rotate 90 degrees counterclockwise again. Either way this rotates the figure a total of 180</span></span>°<span><span> and gives us the desired coordinates.</span></span>
4 0
3 years ago
Read 2 more answers
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