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Morgarella [4.7K]
2 years ago
8

I need help with this​

Mathematics
1 answer:
WARRIOR [948]2 years ago
3 0

Answer:

Is the question or is there more??

Step-by-step explanation:

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The sum of three consecutive rven integers is 72. Let x represent the first integer, x+2 represent the srcond integer, and x+ 4
Vsevolod [243]

Given parameters:

First term of the sequence = x

Second term = x + 2

Third term =  x + 4

Sum of the first three terms  = 72

Unknown:

First term of the sequence = ?

Solution:

The sum of the first three terms is unknown;

            (x) + (x + 2) + (x + 4) = 72

Solve for x;

          x + x + 2 + x + 4  = 72

          3x + 6  = 72

            3x = 72 - 6

              3x = 66

                x = \frac{66}{3}   = 22

The first term of the sequence is 22

5 0
3 years ago
How many positive integers between 1000 and 9999 inclusive
bekas [8.4K]

Answer:

Step-by-step explanation:

a.

first number is  1000-1+9=1008

9)1000(1

    9

-------

     10

       9

    -----

       10

         9

       ----

         1

       ----

last number is 9999

9| 9999

  ---------

    1111 |0

    --------

9999=1008+(n-1)9

9999-1008=(n-1)9

n-1=8991/9=999

n=999+1=1000

b.

first digit=1000

last digit=9999-1=9998

2 |9999

  ---------

  |4999|1

9998=1000+(n-1)2

(n-1)2=9998-1000=8998

n-1=4499

n=4499=1=5000

c.not sure

d.

total  numbers=9000

9999=1000+(n-1)1

9999-1000=n-1

n=8999+1=9000

numbers divisible by 3=3000

first number=1002

last number=9999

9999=1002+(n-1)3

(n-1)3=9999-1002=8997

n-1=2999

n=2999+1=3000

numbers not divisible by 3=9000-3000=6000

e.

numbers divisible by 5=1800

first number=1000

last number=9995

9995=1000+(n-1)5

(n-1)5=9995-1000=8995

n-1=1799

n=1799+1=1800

numbers divisible by 7=1286

7 | 1000

  ---------

  |  142-6

1000-6+7=1001

7 | 9999

  |---------

    1428-3

9999-3=9996

first digit=1001

last digit=9996

9996=1001+(n-1)7

(n-1)7=9996-1001=8995

n-1=1285

n=1285+1=1286

numbers divisible by 35=257

first digit=1015

35 ) 1000 ( 28

        70

       ----

        300

        280

        ------

           20

           ---

1000-20+35=1015

35)9999(285

     70

    ----

     299

     280

     -----

        199

        175

        ----

          24

         ----

last digit=9999-24=9975

9975=1015+(n-1)35

(n-1)35=9975-1015=8960

n-1=8960/35=256

n=257

reqd. numbers=1800+1286-257=3019

7 0
3 years ago
Select True or False for each statement.
grigory [225]

Answer:

1. true

2. true

3. false

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
What is the answer to this????
miss Akunina [59]

Answer:8

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Complete the congruence statement for the figure shown. If the triangles cannot be shown congruent, type na in each blank.
Serjik [45]

Answer:

ΔABC≅ΔDEF by AAS (Angle-Angle-Side) Theorem

Step-by-step explanation:

We observe that \angle A\cong\angle D, \angle C\cong \angle F for the included angle, and BC\cong EF for our side. Thus, the AAS Theorem proves that the triangles are congruent to each other

7 0
2 years ago
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